求一BOM结构视图，高手请进。

[flyfly2008]

有一张Bom表：

goodscode parentitem itemcode model
F0000023 NULL F0000023.1 09864R
SF-7075-*-0-126-2 F0000023.1 SF-7075-*-0-126-2.1 7075
SF-9387-*-0-126-2 F0000023.1 SF-9387-*-0-126-2.1 9387
SF-8971-*-0-126-2 F0000023.1 SF-8971-*-0-126-2.1 8971
F0000043 NULL F0000043.1 09864Q
SF-8971-0-0-222-2 F0000043.1 SF-8971-0-0-222-2.1 8971
SF-7075-0-0-222-2 F0000043.1 SF-7075-0-0-222-2.1 7075
SF-9387-0-0-222-2 F0000043.1 SF-9387-0-0-222-2.1 9387


我要得到如下内容视图：
modelA modelB
09864R 7075
09864R 9387
09864R 8971
09864Q 8971
09864Q 7075
09864Q 9387

就是根据BOM结构关系，把model项一列分解成两列。
参加他们之间关系：select * from Bom where parentitem in (select itemcode from Bom where model='09864Q')

[dawugui]

select m.modelA 
       (select model from bom n where charindex(m.goodscode,n.parentitem) > 0) modelB
from BOM m
where m.parentitem is null

[bancxc]

--只有两层

select modelA=A.model,modelB=B.model
from bom A
join B on A.parentitem is null and b.parentitem is not null
and A.itemcode=B.parentitem

[bancxc]

select modelA=A.model,modelB=B.model
from bom A
join bom B on A.parentitem is null and b.parentitem is not null
and A.itemcode=B.parentitem

[dawugui]

[Quote=引用 1 楼 dawugui 的回复:]
SQL codeselect m.modelA
(select modelfrom bom nwherecharindex(m.goodscode,n.parentitem)>0) modelBfrom BOM mwhere m.parentitemisnull
[/Quote]
我一楼写错了,不好意思.

create table Bom(goodscode  varchar(50),      parentitem varchar(50),           itemcode  varchar(50),            model varchar(50))
insert into bom values('F0000023'         , NULL        , 'F0000023.1'         , '09864R') 
insert into bom values('SF-7075-*-0-126-2', 'F0000023.1', 'SF-7075-*-0-126-2.1', '7075') 
insert into bom values('SF-9387-*-0-126-2', 'F0000023.1', 'SF-9387-*-0-126-2.1', '9387') 
insert into bom values('SF-8971-*-0-126-2', 'F0000023.1', 'SF-8971-*-0-126-2.1', '8971') 
insert into bom values('F0000043'         , NULL        , 'F0000043.1'         , '09864Q') 
insert into bom values('SF-8971-0-0-222-2', 'F0000043.1', 'SF-8971-0-0-222-2.1', '8971') 
insert into bom values('SF-7075-0-0-222-2', 'F0000043.1', 'SF-7075-0-0-222-2.1', '7075') 
insert into bom values('SF-9387-0-0-222-2', 'F0000043.1', 'SF-9387-0-0-222-2.1', '9387')
go

select m.model modelA ,
       n.model modelB
from BOM m , BOM n 
where m.parentitem is null and m.itemcode = n.parentitem
/*
modelA                                             modelB                                             
-------------------------------------------------- -------------------------------------------------- 
09864R                                             7075
09864R                                             9387
09864R                                             8971
09864Q                                             8971
09864Q                                             7075
09864Q                                             9387

（所影响的行数为 6 行）
*/

select m.model modelA ,
       n.model modelB
from BOM m , BOM n 
where m.parentitem is null and charindex(m.goodscode , n.parentitem) > 0
/*
modelA                                             modelB                                             
-------------------------------------------------- -------------------------------------------------- 
09864R                                             7075
09864R                                             9387
09864R                                             8971
09864Q                                             8971
09864Q                                             7075
09864Q                                             9387

（所影响的行数为 6 行）
*/

drop table bom 

[--小F--]

----------------------------------------------------------------
-- Author  :fredrickhu(我是小F，向高手学习)
-- Date    :2009-12-29 09:07:16
-- Version:
--      Microsoft SQL Server 2005 - 9.00.4035.00 (Intel X86) 
--	Nov 24 2008 13:01:59 
--	Copyright (c) 1988-2005 Microsoft Corporation
--	Developer Edition on Windows NT 5.2 (Build 3790: Service Pack 1)
--
----------------------------------------------------------------
--> 测试数据：[tb]
if object_id('[tb]') is not null drop table [tb]
go 
create table [tb]([goodscode] varchar(17),[parentitem] varchar(10),[itemcode] varchar(19),[model] varchar(6))
insert [tb]
select 'F0000023',null,'F0000023.1','09864R' union all
select 'SF-7075-*-0-126-2','F0000023.1','SF-7075-*-0-126-2.1','7075' union all
select 'SF-9387-*-0-126-2','F0000023.1','SF-9387-*-0-126-2.1','9387' union all
select 'SF-8971-*-0-126-2','F0000023.1','SF-8971-*-0-126-2.1','8971' union all
select 'F0000043',null,'F0000043.1','09864Q' union all
select 'SF-8971-0-0-222-2','F0000043.1','SF-8971-0-0-222-2.1','8971' union all
select 'SF-7075-0-0-222-2','F0000043.1','SF-7075-0-0-222-2.1','7075' union all
select 'SF-9387-0-0-222-2','F0000043.1','SF-9387-0-0-222-2.1','9387'
--------------开始查询--------------------------
select
 A.model as modelA,
 B.model as modelB
from
 tb a
join tb b on 
 a.parentitem is null 
and
 b.parentitem is not null
and
 a.itemcode=b.parentitem
and
 charindex(a.goodscode , b.parentitem) > 0


----------------结果----------------------------
/* modelA modelB
------ ------
09864R 7075
09864R 9387
09864R 8971
09864Q 8971
09864Q 7075
09864Q 9387

(6 行受影响)

*/

[playwarcraft]

只有2层？