求一SQL语句，高手请进

flyfly2008 2009-12-30 04:02:08
一个cust表里有数据如下：
custno po color
09864R 7075 126
09864R 9387 126
09864R 8971 126
09864R 9387 291
09864R 7075 291
09864R 8971 291
09864Q 8812 281
09864Q 8813 281
09864Q 8971 222
09864Q 7075 222
09864Q 9387 222

要得到如下结果：
custno po color
09864R 7075-9387-8971 126
09864R 7075-9387-8971 291
09864Q 8812-8813 281
09864Q 7075-9387-8971 222

就是 相同custno 和color 的PO合并一起用“-”隔开


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nianran520 2009-12-31
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samyou 2009-12-31
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學習了。
NDDavid 2009-12-31
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[Quote=引用 7 楼 fredrickhu 的回复:]
SQL code---2000参考
/******************************************************************************************************************************************************
合并分拆表数据

整理人：中国风(Roy)

日期:2?-
[/Quote]
UP
行者_ 2009-12-31
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看看楼上几位 大神
佩服
gao__910 2009-12-30
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学习学习
qiqi860819 2009-12-30
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create table cust

(

custno varchar(6),

po int,

color int

)

go



insert into cust

select '09864R', 7075, 126 union all

select '09864R', 9387, 126 union all

select '09864R', 8971, 126 union all

select '09864R', 9387, 291 union all

select '09864R', 7075, 291 union all

select '09864R', 8971, 291 union all 

select '09864Q', 8812, 281 union all

select '09864Q', 8813, 281 union all

select '09864Q', 8971, 222 union all

select '09864Q', 7075, 222 union all

select '09864Q', 9387, 222

go





alter function dbo.mytt

(

@custno varchar(6)

)

returns varchar(3000)

as

begin

declare @str varchar(3000)

set @str='';

select @str=@str+'-'+cast(po as varchar(4)) from cust where custno=@custno

set @str=substring(@str,2,3000);

return @str

end

go



select custno,dbo.mytt(custno)as t,color from cust group by custno,color
vanjayhsu 2009-12-30
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学习了。。。
z812183667 2009-12-30
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学习了
gxjwqm 2009-12-30
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create table tb (custno varchar(255), po int , color int)



insert into tb

select '09864R', 7075,126 union all

select '09864R', 9387,126 union all

select '09864R', 8971,126 union all

select '09864R', 9387,291 union all

select '09864R', 7075,291 union all

select '09864R', 8971,291 union all

select '09864Q', 8812,281 union all

select '09864Q', 8813,281 union all

select '09864Q', 8971,222 union all

select '09864Q', 7075,222 union all

select '09864Q', 9387,222 





create function fn_test(

@a varchar(255),@b int 

)

returns varchar(200)

as

begin

declare @str varchar(20)

select @str = isnull(@str+'-','')+convert(varchar,po) from tb where custno= @a and  color= @b 



return @str

end

go



select custno,dbo.fn_test(custno,color),color from tb group by custno,color
快乐_石头 2009-12-30
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--小F-- 2009-12-30
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---2000参考

/****************************************************************************************************************************************************** 

合并分拆表数据 



整理人：中国风(Roy) 



日期:2008.06.06 

******************************************************************************************************************************************************/ 



--> --> (Roy)生成測試數據 



if not object_id('Tab') is null 

    drop table Tab 

Go 

Create table Tab([Col1] int,[Col2] nvarchar(1)) 

Insert Tab 

select 1,N'a' union all 

select 1,N'b' union all 

select 1,N'c' union all 

select 2,N'd' union all 

select 2,N'e' union all 

select 3,N'f' 

Go 



合并表: 



SQL2000用函数: 



go 

if object_id('F_Str') is not null 

    drop function F_Str 

go 

create function F_Str(@Col1 int) 

returns nvarchar(100) 

as 

begin 

    declare @S nvarchar(100) 

    select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1 

    return @S 

end 

go 

Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab 



go 



SQL2005用XML: 



方法1: 



select 

    a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'') 

from 

    (select distinct COl1 from Tab) a 

Cross apply 

    (select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b 



方法2: 



select 

    a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44)) 

from 

    (select distinct COl1 from Tab) a 

cross apply 

    (select Col2=(select COl2 from Tab  where COl1=a.COl1 FOR XML AUTO, TYPE) 

                .query(' <Tab> 

                {for $i in /Tab[position() <last()]/@COl2 return concat(string($i),",")} 

                {concat("",string(/Tab[last()]/@COl2))} 

                </Tab>') 

                )b 



SQL05用CTE: 



;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab) 

,Roy2 as 

(select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1 

union all 

select a.Col1,cast(b.COl2+','+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1) 

select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0) 





生成结果: 

/* 

Col1        COl2 

----------- ------------ 

1          a,b,c 

2          d,e 

3          f 



(3 行受影响) 

*/
dawugui 2009-12-30
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--sql 2000用如下函数实现,其他方法见2楼.
create table cust(custno varchar(10), po int,     color int)

insert into cust values('09864R', 7075 ,126 )

insert into cust values('09864R', 9387 ,126 )

insert into cust values('09864R', 8971 ,126 )

insert into cust values('09864R', 9387 ,291 )

insert into cust values('09864R', 7075 ,291 )

insert into cust values('09864R', 8971 ,291 )

insert into cust values('09864Q', 8812 ,281 )

insert into cust values('09864Q', 8813 ,281 )

insert into cust values('09864Q', 8971 ,222 )

insert into cust values('09864Q', 7075 ,222 )

insert into cust values('09864Q', 9387 ,222 )

go



create function dbo.f_str(@custno varchar(10) , @color int) returns varchar(100)

as

begin

    declare @str varchar(1000)

    set @str = ''

    select @str = @str + '-' + cast(po as varchar) from cust where custno = @custno and color = @color

    set @str = right(@str , len(@str) - 1)

    return @str

end

go



--调用函数

select custno , po = dbo.f_str(custno , color) , color from cust group by custno , color



drop function dbo.f_str

drop table cust

/*

custno     po             

---------- ---------------

09864Q     8971-7075-9387                                                                                       222

09864Q     8812-8813                                                                                            281

09864R     7075-9387-8971                                                                                       126

09864R     9387-7075-8971                                                                                       291



（所影响的行数为 4 行）



*/
--小F-- 2009-12-30
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----------------------------------------------------------------

-- Author  :fredrickhu(我是小F，向高手学习)

-- Date    :2009-12-30 16:06:21

-- Version:

--      Microsoft SQL Server 2005 - 9.00.4035.00 (Intel X86) 

--	Nov 24 2008 13:01:59 

--	Copyright (c) 1988-2005 Microsoft Corporation

--	Developer Edition on Windows NT 5.2 (Build 3790: Service Pack 1)

--

----------------------------------------------------------------

--> 测试数据：[tb]

if object_id('[tb]') is not null drop table [tb]

go 

create table [tb]([custno] varchar(6),[po] int,[color] int)

insert [tb]

select '09864R',7075,126 union all

select '09864R',9387,126 union all

select '09864R',8971,126 union all

select '09864R',9387,291 union all

select '09864R',7075,291 union all

select '09864R',8971,291 union all

select '09864Q',8812,281 union all

select '09864Q',8813,281 union all

select '09864Q',8971,222 union all

select '09864Q',7075,222 union all

select '09864Q',9387,222

--------------开始查询--------------------------

select

 custno, 

 [po]=stuff((select '-'+ltrim([po]) from tb  where color=t.color for xml path('')), 1, 1, ''),

 color

from

 [tb] t

group by

  custno,color

----------------结果----------------------------

/*custno po                                                                                                                                                                                                                                                               color

------ ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- -----------

09864Q 8971-7075-9387                                                                                                                                                                                                                                                   222

09864Q 8812-8813                                                                                                                                                                                                                                                        281

09864R 7075-9387-8971                                                                                                                                                                                                                                                   126

09864R 9387-7075-8971                                                                                                                                                                                                                                                   291



(4 行受影响)

 

*/
让你望见影子的墙 2009-12-30
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--> --> (Roy)生成測試數據

 

if not object_id('Tab') is null

    drop table Tab

Go

Create table Tab([Col1] int,[Col2] nvarchar(1))

Insert Tab

select 1,N'a' union all

select 1,N'b' union all

select 1,N'c' union all

select 2,N'd' union all

select 2,N'e' union all

select 3,N'f'

Go



合并表:



SQL2000用函数:



go

if object_id('F_Str') is not null

    drop function F_Str

go

create function F_Str(@Col1 int)

returns nvarchar(100)

as

begin

    declare @S nvarchar(100)

    select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1

    return @S

end

go

Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab



go



SQL2005用XML:



方法1:



select 

    a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'')

from 

    (select distinct COl1 from Tab) a

Cross apply

    (select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b



方法2:



select 

    a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44))

from 

    (select distinct COl1 from Tab) a

cross apply

    (select Col2=(select COl2 from Tab  where COl1=a.COl1 FOR XML AUTO, TYPE)

                .query('<Tab>

                {for $i in /Tab[position()<last()]/@COl2 return concat(string($i),",")}

                {concat("",string(/Tab[last()]/@COl2))}

                </Tab>')

                )b



SQL05用CTE:



;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab)

,Roy2 as

(select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1 

union all 

select a.Col1,cast(b.COl2+','+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1)

select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0)





生成结果:

/*

Col1        COl2

----------- ------------

1           a,b,c

2           d,e

3           f



(3 行受影响)

*/
快乐_石头 2009-12-30
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if object_id('[tb]') is not null drop table [tb]

go

create table [tb] (custno nvarchar(12),po int,color int)

insert into [tb]

select '09864R',7075,126 union all

select '09864R',9387,126 union all

select '09864R',8971,126 union all

select '09864R',9387,291 union all

select '09864R',7075,291 union all

select '09864R',8971,291 union all

select '09864Q',8812,281 union all

select '09864Q',8813,281 union all

select '09864Q',8971,222 union all

select '09864Q',7075,222 union all

select '09864Q',9387,222

select custno,

       po=stuff((select '-'+ltrim(po) from tb where custno=t.custno and color=t.color for xml path('')),1,1,''),

       color

from tb t group by color,custno
dawugui 2009-12-30
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/*

标题：按某字段合并字符串之一(简单合并)

作者：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)

时间：2008-11-06

地点：广东深圳



描述：将如下形式的数据按id字段合并value字段。

id    value

----- ------

1     aa

1     bb

2     aaa

2     bbb

2     ccc

需要得到结果：

id     value

------ -----------

1      aa,bb

2      aaa,bbb,ccc

即：group by id, 求 value 的和（字符串相加）

*/

--1、sql2000中只能用自定义的函数解决

create table tb(id int, value varchar(10))

insert into tb values(1, 'aa')

insert into tb values(1, 'bb')

insert into tb values(2, 'aaa')

insert into tb values(2, 'bbb')

insert into tb values(2, 'ccc')

go



create function dbo.f_str(@id int) returns varchar(100)

as

begin

    declare @str varchar(1000)

    set @str = ''

    select @str = @str + ',' + cast(value as varchar) from tb where id = @id

    set @str = right(@str , len(@str) - 1)

    return @str

end

go



--调用函数

select id , value = dbo.f_str(id) from tb group by id



drop function dbo.f_str

drop table tb





--2、sql2005中的方法

create table tb(id int, value varchar(10))

insert into tb values(1, 'aa')

insert into tb values(1, 'bb')

insert into tb values(2, 'aaa')

insert into tb values(2, 'bbb')

insert into tb values(2, 'ccc')

go



select id, [value] = stuff((select ',' + [value] from tb t where id = tb.id for xml path('')) , 1 , 1 , '')

from tb

group by id



drop table tb





--3、使用游标合并数据

create table tb(id int, value varchar(10))

insert into tb values(1, 'aa')

insert into tb values(1, 'bb')

insert into tb values(2, 'aaa')

insert into tb values(2, 'bbb')

insert into tb values(2, 'ccc')

go

declare @t table(id int,value varchar(100))--定义结果集表变量

--定义游标并进行合并处理

declare my_cursor cursor local for

select id , value from tb

declare @id_old int , @id int , @value varchar(10) , @s varchar(100)

open my_cursor

fetch my_cursor into @id , @value

select @id_old = @id , @s=''

while @@FETCH_STATUS = 0

begin

    if @id = @id_old

       select @s = @s + ',' + cast(@value as varchar)

    else

      begin

        insert @t values(@id_old , stuff(@s,1,1,''))

        select @s = ',' + cast(@value as varchar) , @id_old = @id

      end

    fetch my_cursor into @id , @value

END

insert @t values(@id_old , stuff(@s,1,1,''))

close my_cursor

deallocate my_cursor



select * from @t

drop table tb
jwdream2008 2009-12-30
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