新手servlet问题,为什么报java.util.MissingResourceException

atianatian82 2010-01-03 03:24:35
程序功能是输入first name 和last name并把它们打印出来,不知道为什么总是报错:
java.util.MissingResourceException: Can't find bundle for base name LocalStrings, locale zh_CN
java.util.ResourceBundle.throwMissingResourceException(Unknown Source)
java.util.ResourceBundle.getBundleImpl(Unknown Source)
java.util.ResourceBundle.getBundle(Unknown Source)
RequestParamExample.<init>(RequestParamExample.java:11)

应该是类命名里面的ResourceBundle rb = ResourceBundle.getBundle("LocalStrings");这一句有问题,是不是因为里面的哪个文件不存在而导致的错误?是不是建一个假的文件就可以了。
请问怎么修改?
谢谢。
错误位置应该在RequestParamExample.java里面,但是为了以防万一我把index.jsp和web.xml也贴上来了。
RequestParamExample.java代码如下:

import java.io.*;
import java.text.*;
import java.util.*;
import javax.servlet.*;
import javax.servlet.http.*;


public class RequestParamExample extends HttpServlet {


ResourceBundle rb = ResourceBundle.getBundle("LocalStrings");

public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws IOException, ServletException
{
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<html>");
out.println("<body>");
out.println("<head>");

String title = rb.getString("requestparams.title");
out.println("<title>" + title + "</title>");
out.println("</head>");
out.println("<body bgcolor=\"white\">");
out.println("<h3>" + title + "</h3>");
String firstName = request.getParameter("firstname");
String lastName = request.getParameter("lastname");
out.println(rb.getString("requestparams.params-in-req") + "<br>");
if (firstName != null || lastName != null) {
out.println(rb.getString("requestparams.firstname"));
out.println(" = " + firstName + "<br>");
out.println(rb.getString("requestparams.lastname"));
out.println(" = " + lastName);
} else {
out.println(rb.getString("requestparams.no-params"));
}
out.println("<P>");
out.print("<form action=\"");
out.print("RequestParamExample\" ");
out.println("method=POST>");
out.println(rb.getString("requestparams.firstname"));
out.println("<input type=text size=20 name=firstname>");
out.println("<br>");
out.println(rb.getString("requestparams.lastname"));
out.println("<input type=text size=20 name=lastname>");
out.println("<br>");
out.println("<input type=submit>");
out.println("</form>");

out.println("</body>");
out.println("</html>");
}

public void doPost(HttpServletRequest request,
HttpServletResponse response)
throws IOException, ServletException
{
doGet(request, response);
}

}

index.jsp代码如下:
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<html>
<head>
<title>
Request Parameters Example
</title>
</head>
<form action="/web18/RequestParamExample" method="post">
<p>First Name::::<input type="text" name="firstname" value=""></p>
<p>Last Name::::<input type="text" name="lastname" value=""></p>
<p><input type="submit" name="Submit" value="Submit">
<input type="reset" value="Reset"></p>
</form>
</html>

web.xml代码如下:
<servlet>
<description>This is the description of my J2EE component</description>
<display-name>This is the display name of my J2EE component</display-name>
<servlet-name>RequestParamExample</servlet-name>
<servlet-class>RequestParamExample</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>RequestParamExample</servlet-name>
<url-pattern>/RequestParamExample</url-pattern>
</servlet-mapping>
...全文
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thingkinginchwj 2010-01-03
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可能是没有导util包把
atianatian82 2010-01-03
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自己顶一下,感觉就是那一个函数不懂怎么初始化,请帮忙回答下吧
超超王贱贱 2010-01-03
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查下ResourceBundle的文档吧

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