求一存储过程

yanick007 2010-01-08 04:17:25
表结构如下:
id dept times conten
1 销售部 2010-01-02 13:30:00 ppp
1 销售部 2010-01-03 12:00:00 ccc
2 开发部 2010-01-01 18:20:00 vvv
2 开发部 2010-02-10 15:15:00 eee
3 财务部 2010-03-18 10:00:00 yyy
----------------------------------------------------
要求输入以下结果:
dept oneMonth twoMonth threeMonth
销售部 ppp ccc
开发部 vvv eee
财务部 yyy
----------------------------------------------------
现有sql语句:
select id,dept,oneMonth = case(month(begin_time))
when 1 then content
end
,twoMonth= case(month(begin_time))
when 2 then content
end
,threeMonth= case(month(begin_time))
when 3 then content
end
……
...全文
116 13 打赏 收藏 转发到动态 举报
写回复
用AI写文章
13 条回复
切换为时间正序
请发表友善的回复…
发表回复
bancxc 2010-01-08
  • 打赏
  • 举报
回复
create table tb(id int,dept varchar(10),times datetime,conten varchar(10))
insert into tb select
1,'销售部','2010-01-02 13:30:00','ppp' union all select
1,'销售部','2010-01-03 12:00:00','ccc' union all select
2,'开发部','2010-01-01 18:20:00','vvv' union all select
2,'开发部','2010-02-10 15:15:00','eee' union all select
3,'财务部','2010-03-18 10:00:00','yyy'


DECLARE @STR VARCHAR(1000)
SELECT @STR='select dept'
SELECT @STR=@STR+',['+ LTRIM(M) + ']=MAX(CASE MONTH(TIMES) WHEN '+LTRIM(M)+' THEN CONTEN ELSE '''' END)'
FROM (SELECT DISTINCT MONTH(TIMES) M FROM TB) T

select @STR = @str + ' from (
select dept,times,conten=stuff(b.x,1,1,'''')
from
(
select distinct dept,times
from tb) a cross apply (select '',''+conten from tb b where a.dept=b.dept and month(a.times)=month(b.times)
for xml path('''')) b(x)
)
tb group by dept'
exec(@STR)

财务部 yyy
开发部 vvv eee
销售部 ppp,ccc
yanick007 2010-01-08
  • 打赏
  • 举报
回复
谢谢大家!结贴了
bancxc 2010-01-08
  • 打赏
  • 举报
回复
create table tb(id int,dept varchar(10),times datetime,conten varchar(10))
insert into tb select
1,'销售部','2010-01-02 13:30:00','ppp' union all select
1,'销售部','2010-01-03 12:00:00','ccc' union all select
2,'开发部','2010-01-01 18:20:00','vvv' union all select
2,'开发部','2010-02-10 15:15:00','eee' union all select
3,'财务部','2010-03-18 10:00:00','yyy'


DECLARE @STR VARCHAR(1000)
SELECT @STR='select dept'
SELECT @STR=@STR+',['+ LTRIM(M) + ']=MAX(CASE MONTH(TIMES) WHEN '+LTRIM(M)+' THEN CONTEN ELSE '''' END)'
FROM (SELECT DISTINCT MONTH(TIMES) M FROM TB) T

select @STR = @str + ' from (
select dept,times,conten=stuff(b.x,1,1,'''')
from
(
select distinct dept,times
from tb) a cross apply (select '',''+conten from tb b where a.dept=b.dept and month(a.times)=month(b.times)
for xml path('''')) b(x)
)
tb group by dept'
exec(@STR)
mjluoying 2010-01-08
  • 打赏
  • 举报
回复
呵呵
nianran520 2010-01-08
  • 打赏
  • 举报
回复
--> 测试数据:[tb]
if object_id('[tb]') is not null drop table [tb]
create table [tb]([id] int,[dept] varchar(6),[times] datetime,[content] varchar(3))
insert [tb]
select 1,'销售部','2010-01-02 13:30:00','ppp' union all
select 1,'销售部','2010-01-03 12:00:00','ccc' union all
select 2,'开发部','2010-01-01 18:20:00','vvv' union all
select 2,'开发部','2010-02-10 15:15:00','eee' union all
select 3,'财务部','2010-03-18 10:00:00','yyy'

select * from [tb]

--函数
create function dbo.getcontent(@id int,@month int)
returns varchar(8000)
as
begin
declare @str varchar(8000)
select @str=isnull(@str+' ','')+content from [tb] where id=@id and month(times)=@month
return @str
end
--查询
declare @sql varchar(8000)
select @sql=isnull(@sql+',','')+'max(case month(times) when '+ltrim(times)+' then dbo.getcontent(id,month(times)) else '''' end) as ['+ltrim(times)+']'
from (select distinct month(times) as times from [tb]) t
select @sql='select id,dept,'+@sql+' from tb group by id,dept order by id'
exec(@sql)
百年树人 2010-01-08
  • 打赏
  • 举报
回复
exec sp_test
/**
id dept oneMonth twoMonth threeMonth
1 销售部 ppp,ccc
2 开发部 vvv
2 开发部 eee
3 财务部 yyy
**/
百年树人 2010-01-08
  • 打赏
  • 举报
回复
[Quote=引用 4 楼 josy 的回复:]
SQL code---测试数据---ifobject_id('[tb]')isnotnulldroptable[tb]gocreatetable[tb]([id]int,[dept]varchar(6),[times]datetime,[content]varchar(3))insert[tb]select1,'销售部','2010-01-02 13:30:00','ppp'unionallsel?-
[/Quote]
我也看错了,修正一下
create proc sp_test
as
select id,dept,oneMonth = isnull(case times
when 1 then content
end,'')
,twoMonth= isnull(case times
when 2 then content
end,'')
,threeMonth= isnull(case times
when 3 then content
end,'')
from(
select id,dept,month(times) as times,
content=stuff((select ','+content from tb where id=t.id and dept=t.dept and month(times)=month(t.times) for xml path('')),1,1,'')
from tb t
group by id,dept,month(times)
) t
go
dawugui 2010-01-08
  • 打赏
  • 举报
回复
create table tb(id int, dept varchar(10), times datetime, conten varchar(10))
insert into tb values(1 , '销售部' , '2010-01-02 13:30:00' , 'ppp')
insert into tb values(1 , '销售部' , '2010-01-03 12:00:00' , 'ccc')
insert into tb values(2 , '开发部' , '2010-01-01 18:20:00' , 'vvv')
insert into tb values(2 , '开发部' , '2010-02-10 15:15:00' , 'eee')
insert into tb values(3 , '财务部' , '2010-03-18 10:00:00' , 'yyy')
go

create function dbo.f_str(@id int ,@dept varchar(10), @times varchar(7)) returns varchar(100)
as
begin
declare @str varchar(1000)
set @str = ''
select @str = @str + ',' + cast(conten as varchar) from (select id , dept , conten , times = convert(varchar(7),times,120) from tb) t where id = @id and dept = @dept and times = @times
set @str = right(@str , len(@str) - 1)
return @str
end
go

--调用函数
select dept ,
max(case times when '2010-01' then conten else '' end) [oneMonth],
max(case times when '2010-02' then conten else '' end) [twoMonth],
max(case times when '2010-03' then conten else '' end) [threeMonth]
from
(
select id ,dept , times, conten = dbo.f_str(id ,dept , times) from (select id , dept , conten , times = convert(varchar(7),times,120) from tb) t group by id ,dept , times
) m
group by dept

drop function dbo.f_str
drop table tb

/*
dept oneMonth twoMonth threeMonth
---------- ---------------------------------------------------------------------------------------------------- ---------------------------------------------------------------------------------------------------- ----------------------------------------------------------------------------------------------------
财务部 yyy
开发部 vvv eee
销售部 ppp,ccc

(所影响的行数为 3 行)

*/
yanick007 2010-01-08
  • 打赏
  • 举报
回复
请大家看清楚,要求把content的值根据部门进行合并
求输入以下结果:
dept oneMonth twoMonth threeMonth
销售部 ppp ccc
开发部 vvv eee
财务部 yyy
百年树人 2010-01-08
  • 打赏
  • 举报
回复
---测试数据---
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([id] int,[dept] varchar(6),[times] datetime,[content] varchar(3))
insert [tb]
select 1,'销售部','2010-01-02 13:30:00','ppp' union all
select 1,'销售部','2010-01-03 12:00:00','ccc' union all
select 2,'开发部','2010-01-01 18:20:00','vvv' union all
select 2,'开发部','2010-02-10 15:15:00','eee' union all
select 3,'财务部','2010-03-18 10:00:00','yyy'
go

create proc sp_test
as
select id,dept,oneMonth = isnull(case(month(times))
when 1 then content
end,'')
,twoMonth= isnull(case(month(times))
when 2 then content
end,'')
,threeMonth= isnull(case(month(times))
when 3 then content
end,'')
from tb
go

exec sp_test
/**
id dept oneMonth twoMonth threeMonth
----------- ------ -------- -------- ----------
1 销售部 ppp
1 销售部 ccc
2 开发部 vvv
2 开发部 eee
3 财务部 yyy

(所影响的行数为 5 行)
**/

drop proc sp_test
水族杰纶 2010-01-08
  • 打赏
  • 举报
回复
先函數處理
放臨時表
再行列轉換吧
水族杰纶 2010-01-08
  • 打赏
  • 举报
回复
看走了
還要行列轉換~~
水族杰纶 2010-01-08
  • 打赏
  • 举报
回复
SQL code问题描述:
无论是在sql 2000,还是在 sql 2005 中,都没有提供字符串的聚合函数,
所以,当我们在处理下列要求时,会比较麻烦:
有表tb, 如下:
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
需要得到结果:
id values
------ -----------
1 aa,bb
2 aaa,bbb,ccc
即, group by id, 求 value 的和(字符串相加)

1. 旧的解决方法

-- 1. 创建处理函数
CREATE FUNCTION dbo.f_str(@id int)
RETURNS varchar(8000)
AS
BEGIN
DECLARE @r varchar(8000)
SET @r = ''
SELECT @r = @r + ',' + value
FROM tb
WHERE id=@id
RETURN STUFF(@r, 1, 1, '')
END
GO
-- 调用函数

SELECt id, values=dbo.f_str(id)
FROM tb
GROUP BY id

-- 2. 新的解决方法
-- 示例数据
DECLARE @t TABLE(id int, value varchar(10))
INSERT @t SELECT 1, 'aa'
UNION ALL SELECT 1, 'bb'
UNION ALL SELECT 2, 'aaa'
UNION ALL SELECT 2, 'bbb'
UNION ALL SELECT 2, 'ccc'

-- 查询处理
SELECT *
FROM(
SELECT DISTINCT
id
FROM @t
)A
OUTER APPLY(
SELECT
[values]= STUFF(REPLACE(REPLACE(
(
SELECT value FROM @t N
WHERE id = A.id
FOR XML AUTO
), '<N value="', ','), '"/>', ''), 1, 1, '')
)N

/*--结果
id values
----------- ----------------
1 aa,bb
2 aaa,bbb,ccc
(2 行受影响)
--*/

--各种字符串分函数

--3.3.1 使用游标法进行字符串合并处理的示例。
--处理的数据
CREATE TABLE tb(col1 varchar(10),col2 int)
INSERT tb SELECT 'a',1
UNION ALL SELECT 'a',2
UNION ALL SELECT 'b',1
UNION ALL SELECT 'b',2
UNION ALL SELECT 'b',3

--合并处理
--定义结果集表变量
DECLARE @t TABLE(col1 varchar(10),col2 varchar(100))

--定义游标并进行合并处理
DECLARE tb CURSOR LOCAL
FOR
SELECT col1,col2 FROM tb ORDER BY col1,col2
DECLARE @col1_old varchar(10),@col1 varchar(10),@col2 int,@s varchar(100)
OPEN tb
FETCH tb INTO @col1,@col2
SELECT @col1_old=@col1,@s=''
WHILE @@FETCH_STATUS=0
BEGIN
IF @col1=@col1_old
SELECT @s=@s+','+CAST(@col2 as varchar)
ELSE
BEGIN
INSERT @t VALUES(@col1_old,STUFF(@s,1,1,''))
SELECT @s=','+CAST(@col2 as varchar),@col1_old=@col1
END
FETCH tb INTO @col1,@col2
END
INSERT @t VALUES(@col1_old,STUFF(@s,1,1,''))
CLOSE tb
DEALLOCATE tb
--显示结果并删除测试数据
SELECT * FROM @t
DROP TABLE tb
/*--结果
col1 col2
---------- -----------
a 1,2
b 1,2,3
--*/
GO


/*==============================================*/


--3.3.2 使用用户定义函数,配合SELECT处理完成字符串合并处理的示例
--处理的数据
CREATE TABLE tb(col1 varchar(10),col2 int)
INSERT tb SELECT 'a',1
UNION ALL SELECT 'a',2
UNION ALL SELECT 'b',1
UNION ALL SELECT 'b',2
UNION ALL SELECT 'b',3
GO

--合并处理函数
CREATE FUNCTION dbo.f_str(@col1 varchar(10))
RETURNS varchar(100)
AS
BEGIN
DECLARE @re varchar(100)
SET @re=''
SELECT @re=@re+','+CAST(col2 as varchar)
FROM tb
WHERE col1=@col1
RETURN(STUFF(@re,1,1,''))
END
GO

--调用函数
SELECT col1,col2=dbo.f_str(col1) FROM tb GROUP BY col1
--删除测试
DROP TABLE tb
DROP FUNCTION f_str
/*--结果
col1 col2
---------- -----------
a 1,2
b 1,2,3
--*/
GO

/*==============================================*/


--3.3.3 使用临时表实现字符串合并处理的示例
--处理的数据
CREATE TABLE tb(col1 varchar(10),col2 int)
INSERT tb SELECT 'a',1
UNION ALL SELECT 'a',2
UNION ALL SELECT 'b',1
UNION ALL SELECT 'b',2
UNION ALL SELECT 'b',3

--合并处理
SELECT col1,col2=CAST(col2 as varchar(100))
INTO #t FROM tb
ORDER BY col1,col2
DECLARE @col1 varchar(10),@col2 varchar(100)
UPDATE #t SET
@col2=CASE WHEN @col1=col1 THEN @col2+','+col2 ELSE col2 END,
@col1=col1,
col2=@col2
SELECT * FROM #t
/*--更新处理后的临时表
col1 col2
---------- -------------
a 1
a 1,2
b 1
b 1,2
b 1,2,3
--*/
--得到最终结果
SELECT col1,col2=MAX(col2) FROM #t GROUP BY col1
/*--结果
col1 col2
---------- -----------
a 1,2
b 1,2,3
--*/
--删除测试
DROP TABLE tb,#t
GO


/*==============================================*/

--3.3.4.1 每组 <=2 条记录的合并
--处理的数据
CREATE TABLE tb(col1 varchar(10),col2 int)
INSERT tb SELECT 'a',1
UNION ALL SELECT 'a',2
UNION ALL SELECT 'b',1
UNION ALL SELECT 'b',2
UNION ALL SELECT 'c',3

--合并处理
SELECT col1,
col2=CAST(MIN(col2) as varchar)
+CASE
WHEN COUNT(*)=1 THEN ''
ELSE ','+CAST(MAX(col2) as varchar)
END
FROM tb
GROUP BY col1
DROP TABLE tb
/*--结果
col1 col2
---------- ----------
a 1,2
b 1,2
c 3
--*/

--3.3.4.2 每组 <=3 条记录的合并
--处理的数据
CREATE TABLE tb(col1 varchar(10),col2 int)
INSERT tb SELECT 'a',1
UNION ALL SELECT 'a',2
UNION ALL SELECT 'b',1
UNION ALL SELECT 'b',2
UNION ALL SELECT 'b',3
UNION ALL SELECT 'c',3

--合并处理
SELECT col1,
col2=CAST(MIN(col2) as varchar)
+CASE
WHEN COUNT(*)=3 THEN ','
+CAST((SELECT col2 FROM tb WHERE col1=a.col1 AND col2 NOT IN(MAX(a.col2),MIN(a.col2))) as varchar)
ELSE ''
END
+CASE
WHEN COUNT(*)>=2 THEN ','+CAST(MAX(col2) as varchar)
ELSE ''
END
FROM tb a
GROUP BY col1
DROP TABLE tb
/*--结果
col1 col2
---------- ------------
a 1,2
b 1,2,3
c 3
--*/
GO
if not object_id('A') is null
drop table A
Go
Create table A([id] int,[cname] nvarchar(2))
Insert A
select 1,N'张三' union all
select 2,N'李四' union all
select 3,N'王五' union all
select 4,N'蔡六'
Go
--> -->

if not object_id('B') is null
drop table B
Go
Create table B([id] int,[cname] nvarchar(5))
Insert B
select 1,N'1,2,3' union all
select 2,N'3,4'
Go
create function F_str(@cname nvarchar(100))
returns nvarchar(100)
as
begin
select @cname=replace(@cname,ID,[cname]) from A where patindex('%,'+rtrim(ID)+',%',','+@cname+',')>0
return @cname
end
go
select [id],dbo.F_str([cname])[cname] from B

id cname
----------- ----------------------------------------------------------------------------------------------------
1 张三,李四,王五
2 王五,蔡六

(2 個資料列受到影響)

34,590

社区成员

发帖
与我相关
我的任务
社区描述
MS-SQL Server相关内容讨论专区
社区管理员
  • 基础类社区
  • 二月十六
  • 卖水果的net
加入社区
  • 近7日
  • 近30日
  • 至今
社区公告
暂无公告

试试用AI创作助手写篇文章吧