js mousedown事件怎么获取座标？

guoheng90 2010-01-13 08:58:59

现在页面上有一个显示的div ，我想触发 mousedown事件，如果鼠标不是在div的范围内，
那么就把div给隐藏，不知道如何实现,请高手指点！
最好兼容 firefox和ie

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guoheng90 2010-02-08

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$(document).mousedown(function(event) {
var left = calculateOffset(globalSearchSelector, "offsetLeft");
var top = calculateOffset(globalSearchSelector, "offsetTop");
var width = globalSearchSelector.width();
var height = globalSearchSelector.height();
var top1 = calculateOffset(nav_SearchKeyWord, "offsetTop");
var height1 = nav_SearchKeyWord.height();
//在搜索框和提示层范围外清除提示
if (event.clientX < left || event.clientX > left + width) {
clearItems();
}
else {
if (event.clientY < top || event.clientY > height + top) {
if (event.clientY < top1 || event.clientY > height1 + top1) {
clearItems();
}
}
}
});

千游 2010-01-13

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一弗楚 2010-01-13

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Click_Me 2010-01-13

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你的思路有点问题,跟获取鼠标无关



<body>

<div id="odiv" style="width:100px;height:100px;border:1px solid red;background-color:#D2D2D2"></div>

<script type="text/javascript">

	var O = document.getElementById('odiv');

	document.onmousedown = function() {

		O.style.display = "none";

	}

	O.onmousedown = function(e) {

		!!e ? e.stopPropagation() : event.cancelBubble = true

	}

</script>

</body>

h155290688 2010-01-13

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//获得某个节点的相对坐标

function GetElementPoint(object)

{

    var x=0,y=0;

    while(object.offsetParent)

    {

        

        x+=object.offsetLeft;

        y+=object.offsetTop;

        object=object.offsetParent;

    }

    x+=object.offsetLeft;

    y+=object.offsetTop;

    return {'x':x,'y':y};

}

guoheng90 2010-01-13

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[oElement.x, oElement.y, x2, y2] 里面的四个对象具体是指什么？？
呵呵我是新手!

jianshao810 2010-01-13

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获取某个元素的坐标。
function findPosition(oElement) {
var x2 = 0;
var y2 = 0;
var width = oElement.offsetWidth;
var height = oElement.offsetHeight;
// alert(width + "=" + height);
if (typeof (oElement.offsetParent) != 'undefined') {
for (var posX = 0, posY = 0; oElement; oElement = oElement.offsetParent) {
posX += oElement.offsetLeft;
posY += oElement.offsetTop;
}
x2 = posX + width;
y2 = posY + height;
return [posX, posY, x2, y2];

} else {
x2 = oElement.x + width;
y2 = oElement.y + height;
return [oElement.x, oElement.y, x2, y2];
}
}

h155290688 2010-01-13