分割字符(表中的字段)

lzfrab 2010-01-14 06:51:45

id strs
1 a,b,c,d
2 a,f,g


结果


id str
1 a
1 b
1 c
1 d
2 a
2 f
2 g


请问大虾们怎么能最简单实现?
谢谢
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lzfrab 2010-01-14
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每个id相关的都会多出一个空行,当然可以where的后面增加 and A.[values] is not null 过滤掉,但能不能CHARINDEX的时候就过滤掉

SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b

SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(',', A.[values] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[values], B.id, 1) = ','


谢谢
SQL77 2010-01-14
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----------------------------------------------------------------
-- Author :SQL77(只为思齐老)
-- Date :2010-01-14 18:54:09
-- Version:
-- Microsoft SQL Server 2000 - 8.00.194 (Intel X86)
-- Aug 6 2000 00:57:48
-- Copyright (c) 1988-2000 Microsoft Corporation
-- Desktop Engine on Windows NT 5.1 (Build 2600: Service Pack 3)
--
----------------------------------------------------------------
--> 测试数据:#A
if object_id('tempdb.dbo.#A') is not null drop table #A
go
create table #A([id] int,[strs] varchar(10))
insert #A
select 1,'a,b,c,d,' union all
select 2,'a,f,g,'
--------------开始查询--------------------------

select
ID,
SUBSTRING(strs,NUMBER,CHARINDEX(',',strs+',',NUMBER)-NUMBER)AS strs

from #A,MASTER..SPT_VALUES WHERE TYPE='P'

AND SUBSTRING(','+LEFT(strs,LEN(strs)-1),NUMBER,1)=','
----------------结果----------------------------
/*

(所影响的行数为 2 行)

ID strs
----------- -------
1 a
1 b
1 c
1 d
2 a
2 f
2 g

(所影响的行数为 7 行)


*/


SUBSTRING(','+LEFT(strs,LEN(strs)-1),NUMBER,1)=','
lzfrab 2010-01-14
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id strs
1 a,b,c,d,
2 a,f,g,


如果这样呢?
--小F-- 2010-01-14
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--参考
拆分表:

--> --> (Roy)生成測試數據

if not object_id('Tab') is null
drop table Tab
Go
Create table Tab([Col1] int,[COl2] nvarchar(5))
Insert Tab
select 1,N'a,b,c' union all
select 2,N'd,e' union all
select 3,N'f'
Go

--SQL2000用辅助表:
if object_id('Tempdb..#Num') is not null
drop table #Num
go
select top 100 ID=Identity(int,1,1) into #Num from syscolumns a,syscolumns b
Select
a.Col1,COl2=substring(a.Col2,b.ID,charindex(',',a.Col2+',',b.ID)-b.ID)
from
Tab a,#Num b
where
charindex(',',','+a.Col2,b.ID)=b.ID --也可用 substring(','+a.COl2,b.ID,1)=','
--2000不使用辅助表
Select
a.Col1,COl2=substring(a.Col2,b.number,charindex(',',a.Col2+',',b.number)-b.number)
from
Tab a join master..spt_values b
ON B.type='p' AND B.number BETWEEN 1 AND LEN(A.col2)
where
substring(','+a.COl2,b.number,1)=','


SQL2005用Xml:

select
a.COl1,b.Col2
from
(select Col1,COl2=convert(xml,'<root><v>'+replace(COl2,',','</v><v>')+'</v></root>') from Tab)a
outer apply
(select Col2=C.v.value('.','nvarchar(100)') from a.COl2.nodes('/root/v')C(v))b




SQL05用CTE:

;with roy as
(select Col1,COl2=cast(left(Col2,charindex(',',Col2+',')-1) as nvarchar(100)),Split=cast(stuff(COl2+',',1,charindex(',',Col2+','),'') as nvarchar(100)) from Tab
union all
select Col1,COl2=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from Roy where split>''
)
select COl1,COl2 from roy order by COl1 option (MAXRECURSION 0)

生成结果:
/*
Col1 COl2
----------- -----
1 a
1 b
1 c
2 d
2 e
3 f
*/
SQL77 2010-01-14
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----------------------------------------------------------------
-- Author :SQL77(只为思齐老)
-- Date :2010-01-14 18:54:09
-- Version:
-- Microsoft SQL Server 2000 - 8.00.194 (Intel X86)
-- Aug 6 2000 00:57:48
-- Copyright (c) 1988-2000 Microsoft Corporation
-- Desktop Engine on Windows NT 5.1 (Build 2600: Service Pack 3)
--
----------------------------------------------------------------
--> 测试数据:#A
if object_id('tempdb.dbo.#A') is not null drop table #A
go
create table #A([id] int,[strs] varchar(7))
insert #A
select 1,'a,b,c,d' union all
select 2,'a,f,g'
--------------开始查询--------------------------

select ID,SUBSTRING(strs,NUMBER,CHARINDEX(',',strs+',',NUMBER)-NUMBER)AS strs
from #A,MASTER..SPT_VALUES WHERE TYPE='P' AND SUBSTRING(','+strs,NUMBER,1)=','
----------------结果----------------------------
/*

(所影响的行数为 2 行)

ID strs
----------- -------
1 a
1 b
1 c
1 d
2 a
2 f
2 g

(所影响的行数为 7 行)


*/
bancxc 2010-01-14
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原著:邹建 
改编:爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 2007-12-16 广东深圳

有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc

1. 旧的解决方法(sql server 2000)
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b

SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(',', A.[values] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[values], B.id, 1) = ','

DROP TABLE #

2. 新的解决方法(sql server 2005)

create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
SELECT id, [value] = CONVERT(xml,' <root> <v>' + REPLACE([value], ',', ' </v> <v>') + ' </v> </root>') FROM tb
)A
OUTER APPLY(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)B

DROP TABLE tb

/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
bancxc 2010-01-14
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