XML格式化问题

[qingyanxin]

TransformerFactory tFactory = TransformerFactory.newInstance();
Transformer transformer = tFactory.newTransformer();
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
DOMSource source = new DOMSource(doc);
StringBuffer writeFilePath = new StringBuffer(readFilePath);
writeFilePath.insert(writeFilePath.indexOf("."), "_" + language);
StreamResult result = new StreamResult(writeFilePath.toString());
transformer.transform(source, result);

以上代码生成的XML文件格式如下，想将其格式化，怎么操作呀？生成的XML中空行是由于删除一个节点，如何去掉这个空行呢？最后面两个param是新增的，跟别的也不对齐，请问怎么操作呢？？？？
<Cond name="Cond1">
<param name="a">aa</param>
<param name="b">RequestInfo</param>
<param name="c">1</param>
<param name="d">null</param>
<param name="g">null</param>
<param name="e">hhhhhhhhhhhhhhh</param>
<param name="r">hhhhhhhhhhhhhh</param>
<param name="k">900</param>

<param name="o">hhhhhhhhhh</param>
<param name="p">hhhhhhhhhhhhhhhh</param>
</Cond>

[铁匠梁老师]

工具自动格式化 Altova 不错

[crazylaa]

xml只要数据对，能被解析就好了。为什么一定要对齐呢？