多线程顺序打印

[liyuan19840507]

假设有三个线程 thread1 thread2 thread3 ，第一个线程打印字母‘A’，第二个线程打印字母‘B’，第三个线程打印字母‘C’，要求顺序打印10遍，即打印成‘ABCABC......’


大家觉得该怎么解决啊，谢谢大家啦~~~

[liyuan19840507]

呜呜呜，难道没有人能帮帮我么？

[kone123]

同步处理，或者用互斥也行

[xueer8835]

#include <windows.h>
#include <iostream.h>

DWORD WINAPI Fun1Proc(
LPVOID lpParameter // thread data
);

DWORD WINAPI Fun2Proc(
LPVOID lpParameter // thread data
);
int index=0;
int tickets=100;
HANDLE hMutex;
void main()
{
HANDLE hThread1;
HANDLE hThread2;
hThread1=CreateThread(NULL,0,Fun1Proc,NULL,0,NULL);
hThread2=CreateThread(NULL,0,Fun2Proc,NULL,0,NULL);
CloseHandle(hThread1);
CloseHandle(hThread2);
/*while(index++<1000)
cout<<"main thread is running"<<endl;*/
//hMutex=CreateMutex(NULL,TRUE,NULL);
hMutex=CreateMutex(NULL,TRUE,"tickets");
if(hMutex)
{
if(ERROR_ALREADY_EXISTS==GetLastError())
{
cout<<"only instance can run!"<<endl;
return;
}
}
WaitForSingleObject(hMutex,INFINITE);
ReleaseMutex(hMutex);
ReleaseMutex(hMutex);
Sleep(4000);
// Sleep(10);
}

DWORD WINAPI Fun1Proc(
LPVOID lpParameter // thread data
)
{
/*while(index++<1000)
cout<<"thread1 is running"<<endl;*/

/*while(TRUE)
{
//ReleaseMutex(hMutex);
WaitForSingleObject(hMutex,INFINITE);
if(tickets>0)
{
Sleep(1);
cout<<"thread1 sell ticket : "<<tickets--<<endl;
}
else
break;
ReleaseMutex(hMutex);
}*/

WaitForSingleObject(hMutex,INFINITE);
cout<<"thread1 is running"<<endl;
return 0;
}

DWORD WINAPI Fun2Proc(
LPVOID lpParameter // thread data
)
{

/*while(TRUE)
{
//ReleaseMutex(hMutex);
WaitForSingleObject(hMutex,INFINITE);
if(tickets>0)
{
Sleep(1);
cout<<"thread2 sell ticket : "<<tickets--<<endl;
}
else
break;
ReleaseMutex(hMutex);
}*/
WaitForSingleObject(hMutex,INFINITE);
cout<<"thread2 is running"<<endl;
return 0;
}

给你个类似的例子

[liyuan19840507]

没有人会这个问题么？