线程问题－主程序线程为什么不执行

2010-01-30 09:41:21 217 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

基于拟蒙特卡洛模拟法的随机潮流计算matlab程序由式（4-11）可知，蒙特卡洛模拟法的计算量不受电力系统规模大小影响，因此该方法在一些复杂的电力系统中可以得到应用，包括处理电力系统中有多个间歇性新能源接入的问题，解决系统中多个节点之间相关性问题等等。本章在此基础上提出了基于拟蒙特卡洛模拟的随机潮流计算方法，并且对拟蒙特卡洛法中的拟随机数序列进行了改进，大大提高了随机潮流的计算效率。模拟法的具体思路如下：基于实际工程问题的求解需要，建立与之相对应的随机模拟过程和随机概率模型，使得它们的参数，包括概率分布或者数学期望，能够等于问题的实际解；阅读详情

代码和输出结果如下，问题是
Child #1 joined.
Child #2 joined.
Child #3 joined.
这三个主程序的语句为什么在最后执行？当其它线程sleep的时候，主程序还不能执行吗？
为什么？谢谢！

using System;
using System.Threading;

class MyThread
{
public int count;
public Thread thrd;

public MyThread(string name)
{
count = 0;
thrd = new Thread(run);
thrd.Name = name;
thrd.Start();
}

void run()
{
Console.WriteLine(thrd.Name + " starting.");

do
{
Thread.Sleep(1000);
Console.WriteLine("In " + thrd.Name +
", count is " + count);
count++;
} while (count < 5);

Console.WriteLine(thrd.Name + " terminating.");
}
}

class MainClass
{
public static void Main()
{
Console.WriteLine("Main thread starting.");

MyThread mt1 = new MyThread("Child #1");
MyThread mt2 = new MyThread("Child #2");
MyThread mt3 = new MyThread("Child #3");

mt1.thrd.Join();
Console.WriteLine("Child #1 joined.");

mt2.thrd.Join();
Console.WriteLine("Child #2 joined.");

mt3.thrd.Join();
Console.WriteLine("Child #3 joined.");

Console.WriteLine("Main thread ending.");

Console.ReadLine();
}
}

这是输出结果：
Main thread starting.
Child #1 starting.
Child #2 starting.
Child #3 starting.
In Child #2, count is 0
In Child #1, count is 0
In Child #3, count is 0
In Child #2, count is 1
In Child #1, count is 1
In Child #3, count is 1
In Child #2, count is 2
In Child #1, count is 2
In Child #3, count is 2
In Child #2, count is 3
In Child #1, count is 3
In Child #3, count is 3
In Child #2, count is 4
Child #2 terminating.
In Child #1, count is 4
Child #1 terminating.
In Child #3, count is 4
Child #3 terminating.
Child #1 joined.
Child #2 joined.
Child #3 joined.
Main thread ending.

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