求助，jQuery拿不到返回值。。

[o0zone777]

ActionBean:

public ActionForward doCheckUser(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) throws IOException {

Icp_zcForm icp_zcForm = null;
IIcp_zcService icp_zc = new Icp_zcServiceImpl();
String username="";
if(request.getParameter("username")!=null){
username = request.getParameter("username");
}
List list = icp_zc.getUserUnique(username, this.getServlet().getServletContext());
if(list!=null){
if(list.size()!=1){
System.out.println("Fail");
response.getWriter().print("您申请的用户名称已被占用");
return mapping.findForward("icp_first_zc");
}else{
System.out.println("Succ");
response.getWriter().print("恭喜您!您可以使用这个用户名!");
return mapping.findForward("icp_first_zc");
}
}
return null;

}
}

JS

CheckUser=function(ContextPath){
var username = (document.getElementById('icp_zc_1')).value;

if(username==""){
alert('用户名不能为空!')
(document.getElementById('icp_zc_1')).focues();
return false;
}
var pat=ContextPath+"/icp/icp_zc.do?method=doCheckUser&username="+username;
$.get(pat,null,function(responseTxt){
alert(responseTxt);});
}

responseTxt拿回来了发出请求的网页的源码。。。晕。。。求各位大侠帮忙

[crazylaa]

[Quote=引用楼主 o0zone777 的回复:]
responseTxt拿回来了发出请求的网页的源码。。。晕。。。求各位大侠帮忙
[/Quote]
赶紧取拿别的网站，源码啊！很珍贵的。。。

jquery不懂的帮顶。

[zhj92lxs]

return mapping.findForward("icp_first_zc");
这个换成return null试试

[o0zone777]

哦了~~return null搞定~

[xinlan1022]

return null;试试