CString::Mid() 简单问题

[Althonx1024]

		CString strtmp;
		strtmp.Format(_T("123sd#<FileName>xxx234@!asd%%wr3</FileName>"));
		int nLength = strtmp.GetLength();

		CString strFindBeg;
		CString strFindEnd;
		strFindBeg.Format(_T("<FileName>"));
		strFindEnd.Format(_T("</FileName>"));

		int nBeg = 0;
		int nEnd = 0;

		nBeg = strtmp.Find(strFindBeg);
		nEnd = strtmp.Find(strFindEnd);

		TCHAR testChar = _T('\0');
		testChar = strtmp.GetAt(nEnd); // '<'

		CString strTarget;
		strTarget = strtmp.Mid(nBeg + strFindBeg.GetLength(), nEnd/* - strFindEnd.GetLength()*/);
		AfxMessageBox(strTarget);

Questions::
1. 为什么最后的strTarget显示的字符串要多显示5个字符"</File"

2. 要求是只显示<FileName>和</FileName>中间的字符串.求解

[「已注销」]

		CString strtmp;
		strtmp.Format(_T("123sd#<FileName>xxx234@!asd%%wr3</FileName>asdfasaerqwer23412df"));
		int nLength = strtmp.GetLength();

		CString strFindBeg;
		CString strFindEnd;
		strFindBeg.Format(_T("<FileName>"));
		strFindEnd.Format(_T("</FileName>"));


		int nBeg = 0;
		int nEnd = 0;

		nBeg = strtmp.Find(strFindBeg);
		nEnd = strtmp.Find(strFindEnd);

		TCHAR testChar = _T('\0');
		testChar = strtmp.GetAt(nEnd);

		CString strTarget;
		strTarget = strtmp.Mid(nBeg + strFindBeg.GetLength(), nEnd/* - strFindEnd.GetLength()*/);
		AfxMessageBox(strTarget);

这样strTarget的值是xxx234@!asd%wr3</FileName>asdfa

[「已注销」]

CString Mid( int nFirst, int nCount ) const;

谢谢, 没注意看函数声明....