线程 synchronized
public class TT implements Runnable {
int b=100;
public void run() {
try {
m1();
} catch (Exception e) {
e.printStackTrace();
}
}
public synchronized void m1() throws Exception{
b=1000;
Thread.sleep(5000);
System.out.println("b="+b);
}
public void m2() throws Exception{
Thread.sleep(2500);
b=2000;
}
public static void main(String[] args) throws Exception {
TT tt=new TT();
Thread t=new Thread(tt);
t.start();
tt.m2();
}
}
输出b=2000;
m2方法前面 synchronized,输出b=1000;
为什么是这两种结果,请大家帮忙分析一下。谢谢