求合并这样的字符串...急！

[TimLeaf]

这样的数据：
col1 col2 col3 col4
80 1 1 2
80 1 1 5
80 1 1 1
80 1 1 4
80 1 1 3
80 1 2 4
80 1 2 1
80 1 2 2
80 1 3 5
80 1 3 1
80 1 3 3
80 1 3 2

要求合并成
col1 col2 col3 col4
80 1 1 1,2,3,4,5
80 1 2 1,2,4
80 1 3 1,2,3,5

谢谢大家了...

[bancxc]

合并列值 
原著：邹建 
改编：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)  2007-12-16  广东深圳 

表结构，数据如下： 
id    value 
----- ------ 
1    aa 
1    bb 
2    aaa 
2    bbb 
2    ccc 

需要得到结果： 
id    values 
------ ----------- 
1      aa,bb 
2      aaa,bbb,ccc 
即：group by id, 求 value 的和（字符串相加） 

1. 旧的解决方法(在sql server 2000中只能用函数解决。) 
--1. 创建处理函数 
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 

CREATE FUNCTION dbo.f_str(@id int) 
RETURNS varchar(8000) 
AS 
BEGIN 
    DECLARE @r varchar(8000) 
    SET @r = '' 
    SELECT @r = @r + ',' + value FROM tb WHERE id=@id 
    RETURN STUFF(@r, 1, 1, '') 
END 
GO 

-- 调用函数 
SELECt id, value = dbo.f_str(id) FROM tb GROUP BY id 

drop table tb 
drop function dbo.f_str 

/* 
id          value      
----------- ----------- 
1          aa,bb 
2          aaa,bbb,ccc 
（所影响的行数为 2 行） 
*/ 

--2、另外一种函数. 
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 

--创建一个合并的函数 
create function f_hb(@id int) 
returns varchar(8000) 
as 
begin 
  declare @str varchar(8000) 
  set @str = '' 
  select @str = @str + ',' + cast(value as varchar) from tb where id = @id 
  set @str = right(@str , len(@str) - 1) 
  return(@str) 
End 
go 

--调用自定义函数得到结果： 
select distinct id ,dbo.f_hb(id) as value from tb 

drop table tb 
drop function dbo.f_hb 

/* 
id          value      
----------- ----------- 
1          aa,bb 
2          aaa,bbb,ccc 
（所影响的行数为 2 行） 
*/ 

2. 新的解决方法(在sql server 2005中用OUTER APPLY等解决。) 
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 
-- 查询处理 
SELECT * FROM(SELECT DISTINCT id FROM tb)A OUTER APPLY( 
        SELECT [values]= STUFF(REPLACE(REPLACE( 
            ( 
                SELECT value FROM tb N 
                WHERE id = A.id 
                FOR XML AUTO 
            ), ' <N value="', ','), '"/>', ''), 1, 1, '') 
)N 
drop table tb 

/* 
id          values 
----------- ----------- 
1          aa,bb 
2          aaa,bbb,ccc 

(2 行受影响) 
*/ 

--SQL2005中的方法2 
create table tb(id int, value varchar(10)) 
insert into tb values(1, 'aa') 
insert into tb values(1, 'bb') 
insert into tb values(2, 'aaa') 
insert into tb values(2, 'bbb') 
insert into tb values(2, 'ccc') 
go 

select id, [values]=stuff((select ','+[value] from tb t where id=tb.id for xml path('')), 1, 1, '') 
from tb 
group by id 

/* 
id          values 
----------- -------------------- 
1          aa,bb 
2          aaa,bbb,ccc 

(2 row(s) affected) 

*/ 

drop table tb 

[ws_hgo]

。。。。。

[中国风]

use Tempdb
go
--> --> 
 
if not object_id(N'Tempdb..#T2') is null
	drop table #T2
Go
Create table #T2([col1] int,[col2] int,[col3] int,[col4] int)
Insert #T2
select 80,1,1,2 union all
select 80,1,1,5 union all
select 80,1,1,1 union all
select 80,1,1,4 union all
select 80,1,1,3 union all
select 80,1,2,4 union all
select 80,1,2,1 union all
select 80,1,2,2 union all
select 80,1,3,5 union all
select 80,1,3,1 union all
select 80,1,3,3 union all
select 80,1,3,2
Go
Select [col1],[col2],[col3], [col4]=stuff((select ','+rtrim([col4]) from #T2 where  [col1]=a.[col1] and [col2]=a.[col2] and [col3]=a.[col3] order by [col4] for xml path('')),1,1,'')
from #T2 a 
group by [col1],[col2],[col3]

[中国风]

其它方法參照
http://topic.csdn.net/u/20080612/22/c850499f-bce3-4877-82d5-af2357857872.html?22837

[TimLeaf]

[Quote=引用 1 楼 bancxc 的回复:]

SQL code
合并列值
原著：邹建
改编：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 2007-12-16 广东深圳

表结构，数据如下：
id value
----- ------
1 aa
1 bb
2 aaa
2 bbb
2 ccc

需要得到结果：
id values
------ ----------- ……
[/Quote]
这个代码我看过...我比较笨...不知道怎么使用...

[--小F--]

Select
 [col1],[col2],[col3], [col4]=stuff((select ','+rtrim([col4]) from tb where  [col1]=a.[col1] and [col2]=a.[col2] and [col3]=a.[col3] order by [col4] for xml path('')),1,1,'')
from
 tb a 
group by
 [col1],[col2],[col3]

[TimLeaf]

啊...忘记说了...
是SqlServer 2000

[yhtapmys]

[Quote=引用 7 楼 timleaf 的回复:]
啊...忘记说了...
是SqlServer 2000
[/Quote]

if not object_id('T2') is null
    drop table T2
Go
Create table T2([col1] int,[col2] int,[col3] int,[col4] int)
Insert T2
select 80,1,1,2 union all
select 80,1,1,5 union all
select 80,1,1,1 union all
select 80,1,1,4 union all
select 80,1,1,3 union all
select 80,1,2,4 union all
select 80,1,2,1 union all
select 80,1,2,2 union all
select 80,1,3,5 union all
select 80,1,3,1 union all
select 80,1,3,3 union all
select 80,1,3,2
Go

--创建一个合并的函数 
create function f_hb(@col1 int,@col2 int,@col3 int) 
returns varchar(8000) 
as 
begin 
  declare @str varchar(8000) 
  set @str = '' 
  select @str = @str + ',' + cast(col4 as varchar) from t2 where col1 = @col1 and col2 = @col2 and col3 = @col3 order by col4
  set @str = right(@str , len(@str) - 1) 
  return(@str) 
End 
go 

--查询
select distinct col1,col2,col3,dbo.f_hb(col1,col2,col3) as col4 from t2

--结果
/*
col1 col2 col3 col4
----------------------------------
80	1	1	1,2,3,4,5
80	1	2	1,2,4
80	1	3	1,2,3,5
*/

[TimLeaf]

函数效率可够低...