select (sum( )/count(*)
mac_h 2010-03-27 10:18:54 select (sum(chailv)/count(*)-sum([MoneyList].MoneyCost)) as InsertOk from [ProjectCosts],[MoneyList] where ([ProjectCosts].ProjectNumber=[MoneyList].ProjectNum ) and ([ProjectCosts].ProjectNumber='" + ProjectNumber + "' ) and [MoneyList].state=1";
这句话是和意思啊