数组转字符串

[aoxianglin]

String a[] = {"1","2","3","4","5"}
转成
String b= "1,2,3,4,5"


new String跟toString
两个都报错？

[soton_dolphin]

String a[] = {"1","2","3","4","5"};
String b="";
for(int i=0;i<(a.length);i++){
b += (a[i]+", ");
}

[soton_dolphin]

String a[] = {"1","2","3","4","5"};
String b="";
for(int i=0;i<a.length;i++){
b += (a[i]+", ");
}

[Ark032425]

[Quote=引用 1 楼 amos1989 的回复:]
肯定不行啦。。。
用这个方法
StringBuilder sb = new StringBuilder();
for(int i=0;i<a.length;i++){
sb.append(a[i]);
if(i!=a.length){
ab.append(",");
}
}
sb.toString();
就可以了
[/Quote]
中间有个“，”；需要自己搞

[Arthur0088]

[Quote=引用 3 楼 soton_dolphin 的回复:]
String a[] = {"1","2","3","4","5"};
String b="";
for(int i=0;i<a.length;i++){
b += (a[i]+", ");
}
[/Quote]

支持这种做法

[liu_siat]

String a[] = {"1","2","3","4","5"};
StringBuffer b=new StringBuffer();
for(int i=0;i<a.length-1;i++){
b.append (a[i]+", ");
}
b.append(a[a.length-1]);
此答案应更好

[Dazzlingwinter]

String a[] = {"1","2","3","4","5"};
		return "\"" + Arrays.toString(a).substring(1, Arrays.toString(a).length()-1) + "\"";

[amos1989]

[Quote=引用 5 楼 arthur0088 的回复:]
引用 3 楼 soton_dolphin 的回复:
String a[] = {"1","2","3","4","5"};
String b="";
for(int i=0;i<a.length;i++){
b += (a[i]+", ");
}


支持这种做法
[/Quote]
如果你理解String你就觉得这种做法是效率最低的..

[amos1989]

[Quote=引用 7 楼 dazzlingwinter 的回复:]
Java code

String a[] = {"1","2","3","4","5"};
return "\"" + Arrays.toString(a).substring(1, Arrays.toString(a).length()-1) + "\"";
[/Quote]
学习了...呵呵一下子忽略了Arrays,不过只有在JDK1.6的版本中才可以使用.而且觉得根据他的意思,前面和后面的"(双引号)是不需要的了,

[长公子冰]

见识了 虽然有JDK6 但一直没用 新特性也不了解 呵呵

[hjh811]

[Quote=引用 7 楼 dazzlingwinter 的回复:]
Java code

String a[] = {"1","2","3","4","5"};
return "\"" + Arrays.toString(a).substring(1, Arrays.toString(a).length()-1) + "\"";
[/Quote]好简洁 学习了

[Trinx]

String a[] = {"1","2","3","4","5"};
System.out.println(Arrays.toString(a).replaceAll("\\[|\\]","\""));

[amos1989]

肯定不行啦。。。
用这个方法
StringBuilder sb = new StringBuilder();
for(int i=0;i<a.length;i++){
sb.append(a[i]);
if(i!=a.length){
ab.append(",");
}
}
sb.toString();
就可以了