难道又是缓冲区问题

[starcat]

书上例子：

#include <string>
#include <iostream>
using namespace std;
int main() {
string first("This");
string second("That");
// Which is lexically greater?
switch(first.compare(second)) {
case 0: // The same
cout << first << " and " << second <<
" are lexically equal" << endl;
break;
case -1: // Less than
first.swap(second);
// Fall through this case...
case 1: // Greater than
cout << first <<
" is lexically greater than " <<
second << endl;
}
}

结果，没有输出……

[lovesi3344]

#include <string>
#include <iostream>
using namespace std;
int main() 
{
    string first("This");
    string second("That");
    // Which is lexically greater?
    switch(first.compare(second)) 
    {
          case 0: // The same
          cout << first << " and " << second <<" are lexically equal" << endl;break;
          case -1: // Less than
          first.swap(second);
          // Fall through this case...
          case 1: // Greater than
          cout << first <<" is lexically greater than " <<second << endl;
    }
    system("pause");//mark
}

[stardust20]

试了下。。输出This is lexically greater than That

[lovesi3344]

加上这句
system("pause");//mark

[starcat]

呃，不是这个问题啊
我用的BCC 5.5命令行编译器，本来就不用加暂停的

[lovesi3344]

我加完就输出了2楼的结果
难道不是吗？

[Quote=引用 4 楼 starcat 的回复:]
呃，不是这个问题啊
我用的BCC 5.5命令行编译器，本来就不用加暂停的
[/Quote]

[yuzl32]

'i' - 'a' = 8

[buptzwp]

g++下没问题呀，compare()怎么会返回8呀？

[scudc]

vc6.0可以输出。。。。。。。。。。。。

[starcat]

原因找到了，我这儿compare()的返回值是8，看来是我人品不好了

#include <string>
#include <iostream>
using namespace std;
int main() {
string first("This");
string second("That");
int i;
// Which is lexically greater?
switch(i = first.compare(second)) {
case 0: // The same
cout << first << " and " << second <<
" are lexically equal" << endl;
break;
case -1: // Less than
first.swap(second);
// Fall through this case...
case 1: // Greater than
cout << first <<
" is lexically greater than " <<
second << endl;
}
cout << "i = " << i << endl;
}