如何分割数组里面的字符串？

[fondax]

string[] arr = File.ReadAllLines("SouthGustaberg-2floor.txt");

我现在读取了一些数据放入了arr这个数组里面
[0] "267.3595 -320.5231" string
[1] "265.2567 -320.4095" string
[2] "260.7415 -320.164" string
[3] "256.3372 -319.9459" string
[4] "251.8748 -319.731" string
[5] "247.3086 -319.5264" string
[6] "242.776 -319.3187" string
[7] "238.7804 -317.9861" string
[8] "234.6706 -316.0398" string
我还想把这个arr分割成2个数组（例如[0]267.3595，[0]-320.5231），或者分割成一个二维数组，应该怎么写好？

[threenewbee]

dim arr2(,) as string
dim arr3() as string
redim arr2(0 to ubound(arr), 2)
for i = 0 to ubound(arr)
arr3 = split(arr(i), " ")
arr2(i, 0) = arr3(0)
arr2(i, 1) = arr3(1)
next

[hzxsasdfgh]

[Quote=引用 1 楼 caozhy 的回复:]

dim arr2(,) as string
dim arr3() as string
redim arr2(0 to ubound(arr), 2)
for i = 0 to ubound(arr)
arr3 = split(arr(i), " ")
arr2(i, 0) = arr3(0)
arr2(i, 1) = arr3(1)
next
[/Quote]
额~这个是vb吧！

[JacksonFox]

现在这个时代，语言都是相通的，关键是想法和算法。顶二楼的。

[wuyi8808]

string[] arr = File.ReadAllLines("SouthGustaberg-2floor.txt");
string[] arr1 = new string[arr.Length];
string[] arr2 = new string[arr.Length];
for (int i = 0; i < arr.Length; i++)
{
  string[] t = arr[i].Split(' ');
  arr1[i] = t[0];
  arr2[i] = t[1];
}

[wuyq11]

int[,] array1 = new int[arr.length, 2];
foreach(string s in arr)
{
string[] arr2=s.Split(new string[] { "-" }, StringSplitOptions.RemoveEmptyEntries);

}

[threenewbee]

[Quote=引用 2 楼 hzxsasdfgh 的回复:]
引用 1 楼 caozhy 的回复:

dim arr2(,) as string
dim arr3() as string
redim arr2(0 to ubound(arr), 2)
for i = 0 to ubound(arr)
arr3 = split(arr(i), " ")
arr2(i, 0) = arr3(0)
arr2(i, 1) = arr3(1)
nex……
[/Quote]

不好意思看错了。

LZ以前一直问VB的，怎么突然搞C#了，晕。

[yufenghua]

抓住关键，split

[Peter200694013]

String[] arr = File.ReadAllLines("SouthGustaberg-2floor.txt");
String[] arr1 = new String[arr.Length];
String[] arr2 = new String[arr.Length];
for (int i = 0; i < arr.Length; i++)
{
String[] temp = arr[i].Split(' ');
arr1[i] = temp[0];
arr2[i] = temp[1];
}

[xrongzhen]

string[] arr = File.ReadAllLines("SouthGustaberg-2floor.txt");
string[] arr1 = new string[arr.Length];
string[] arr2 = new string[arr.Length];
for (int i = 0; i < arr.Length; i++)
{
  string[] t = arr[i].Split(' ');
  arr1[i] = t[0];
  arr2[i] = t[1];
}

[codeingsky]

string[] t = arr[i].Split(' ');

[hacker1125]

抓住关键，split.
还有你分割点有‘-’
就可以根据这个分割了

[njyang110]

用泛型集合存：

string[] arr = File.ReadAllLines("SouthGustaberg-2floor.txt");
Dictionary<string, string> D = new Dictionary<string, string>();
arr[0]=.....
....
for(int i=0;i<arr.Length;i++)
{
string[] t = arr[i].Split('-');
d.add("","");
}

大概是这样`手写的

[shang123guan]

不重复别人的正确答案了

[wxxloveu]

这里有个应该是字符串问题，帮忙看下
http://topic.csdn.net/u/20100413/08/df945aa0-ea71-4042-887e-f714f78d5b80.html