关于webservice传递参数的问题

gaohongtao_2005 2010-04-15 11:31:29

各位：我想用java调用.net的webservice

webservice的代码如下：



using System;

using System.Linq;

using System.Web;

using System.Web.Services;

using System.Web.Services.Protocols;

using System.Xml.Linq;



[WebService(Namespace = "http://tempuri.org/")]

[WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]

// 若要允许使用 ASP.NET AJAX 从脚本中调用此 Web 服务，请取消对下行的注释。

// [System.Web.Script.Services.ScriptService]

public class Service : System.Web.Services.WebService

{

    public Service() {



        //如果使用设计的组件，请取消注释以下行 

        //InitializeComponent(); 

       

    }



    [WebMethod]

    public string HelloWorld() {

        return "你好你好";

    }



    [WebMethod]

    public string MyMethod(String userID)

    {

        return "欢迎您：" + userID +"先生";

    }

}

java调用的代码如下



public void test(String userID)

	{

		try

		{

			String endpoint = "http://localhost:3474/MyWebService/Service.asmx";

			Service service = new Service();

			Call call = (Call) service.createCall();

			call.setTargetEndpointAddress(endpoint);

			//call.setOperationName(new QName(endpoint,"MyMethod"));

			call.setOperationName("MyMethod");

			//call.addParameter("mypar", org.apache.axis.encoding.XMLType.XSD_DATE,javax.xml.rpc.ParameterMode.IN);

			call.addParameter("userID", XMLType.XSD_STRING, ParameterMode.IN);

			//call.addParameter("alarmHours", XMLType.XSD_STRING, ParameterMode.IN);

			call.setReturnType(org.apache.axis.encoding.XMLType.XSD_STRING);

			call.setUseSOAPAction(true);

			call.setSOAPActionURI("http://tempuri.org/MyMethod");		

			String result = (String)call.invoke(new Object[]{ userID });

			System.out.println("显示结果——>"+result);

		}

		catch(Exception ex)

		{

			System.out.println("Error: "+ex);

		}

	}