【求正则】要求把json串中“:”前面名称部分的双引号去掉，值中的双引号保留

[BillyW]

求一个正则表达式：

要求把json串中“:”前面名称部分的双引号去掉，值中的双引号保留。如下例：
原字符串：
[{"attributes":{"id":"1"},"children":[{"attributes":{"id":"11"},"children":[],"data":"name11","state":"open"},{"attributes":{"id":"12"},"children":[],"data":"name12","state":"open"}],"data":"name1","state":"open"},{"attributes":{"id":"2"},"children":[],"data":"name2","state":"open"}]

我需要的字符串：(注意“冒号”前面名称部分的引号没有了，值中的引号是保留的。
[{attributes:{id:"1"},children:[{attributes:{id:"11"},children:[],data:"name11",state:"open"},{attributes:{id:"12"},children:[],data:"name12",state:"open"}],data:"name1",state:"open"},{attributes:{id:"2"},children:[],data:"name2",state:"open"}]



感谢正则达人了~~~~

[王集鹄]

str = str.replace(/"(\w+)":/g, "$1:");

[王集鹄]

兼容一下有空格的情况：
str = str.replace(/"(\w+)"(\s*:\s*)/g, "$1$2");

推荐正则调试工具：http://www.renrousousuo.com/tools/regex_debug.html

[Jeffrey84]

1楼的就可以了

[BillyW]

感谢zswang

如果在java服务层代码里写，应该怎么做呢？

[王集鹄]

正在学习java。

import java.util.regex.*;

public class Main {
    public static void main(String[] args) {
        String json = "{name:\"value\"}";
        Pattern p = Pattern.compile("/\"(\\w+)\"(\\s*:/\\s*)");
        Matcher m = p.matcher(json);
        String t = m.replaceAll("$1$2");
        System.out.println(t);
    }
}

[BillyW]

如果在java服务层代码里写，应该怎么写呢？

[shan1119]

str=str.replaceAll("\\"([^\\"]+?)\\"[:]","\\1");

[shan1119]

[Quote=引用 7 楼 shan1119 的回复:]
str=str.replaceAll("\\"([^\\"]+?)\\"[:]","\\1");
[/Quote]
不対,是 str=str.replaceAll("\\"([^\\"]+?)\\"[:]","$1");

[BillyW]

这样写结果不正确，错误的结果是这样的：
{"{\"attributes\":{\"id\":\"1\"},\"children\":[{\"attributes\":{\"id\":\"11\"},\"children\":[],\"data\":\"name11\",\"state\":\"open\"},{\"attributes\":{\"id\":\"12\"},\"children\":[],\"data\":\"name12\",\"state\":\"open\"}],\"data\":\"name1\",\"state\":\"open\"}":{attributes:{id:"1"},children:[{attributes:{id:"11"},children:[],data:"name11",state:"open"},{attributes:{id:"12"},children:[],data:"name12",state:"open"}],data:"name1",state:"open"},"{\"attributes\":{\"id\":\"2\"},\"children\":[],\"data\":\"name2\",\"state\":\"open\"}":{attributes:{id:"2"},children:[],data:"name2",state:"open"}}




[Quote=引用 5 楼 zswang 的回复:]
正在学习java。

Java code
import java.util.regex.*;

public class Main {
public static void main(String[] args) {
String json = "{name:\"value\"}";
Pattern p = Pattern.compile("……
[/Quote]

[BillyW]

通过了。谢谢zswang，我的代码刚才有bug。

结贴

[王集鹄]

多了几个/
Pattern p = Pattern.compile("\"(\\w+)\"(\\s*:\\s*)");

[王集鹄]

原来String就有这个方法：

public class Main {
    public static void main(String[] args) {
        String json = "{\"name\":\"value\"}";
        String t = json.replaceAll("\"(\\w+)\"(\\s*:\\s*)", "$1$2");
        System.out.println(t);
    }
}