问个byte数组的问题

[_梦]

有个int i=12345678;
怎么放入4长度的byte[] b=new byte[4]中，坐等强人！

[火龙果被占用了]

字节序采用 Big-Endian 还是 Little-Endian？

[_梦]

啊....默认是啥就是啥

[fephy]

都搞java
c++没人理财了么？

[火龙果被占用了]

public class ScoreTest {

    public static void main(String[] args) {
        byte[] be = int2BytesBE(0xcc123abc);
        System.out.println(ByteUtil.bytes2StrSpace(be));

        byte[] le = int2BytesLE(0xcc123abc);
        System.out.println(ByteUtil.bytes2StrSpace(le));
    }

    public static byte[] int2BytesBE(int num) {
        return int2Bytes(num, true);
    }

    public static byte[] int2BytesLE(int num) {
        return int2Bytes(num, false);
    }

    public static byte[] int2Bytes(int num, boolean isBigEndian) {
        final int len = Integer.SIZE / Byte.SIZE;
        byte[] bys = new byte[len];
        for(int i = 0; i < len; i++) {
            int shift = isBigEndian ? (len - 1 - i) * Byte.SIZE : (i * Byte.SIZE);
            bys[i] = (byte)((num >>> shift) & 0xff);
        }
        return bys;
    }
}

class ByteUtil {

    private final static char[] HEX = "0123456789abcdef".toCharArray();

    private ByteUtil() { }

    public static String bytes2StrSpace(byte[] bys) {
        char[] chs = new char[bys.length * 3 - 1];
        for(int i = 0, k = 0; i < bys.length; i++) {
            if(k > 0) {
                chs[k++] = ' ';
            }
            chs[k++] = HEX[(bys[i] >> 4) & 0xf];
            chs[k++] = HEX[bys[i] & 0xf];
        }
        return new String(chs);
    }
}

[_梦]

我晕，这么多

[keeya0416]

写个蛋疼的硬编码

public class Test {
	public static void main(String[] args) {
		int i=12345678;
		byte[] b=new byte[4];
		for(int m = 0; m < b.length; m++){
			b[m] =(byte)( i % 100);
			i /= 100;
		}
	}
}

[_梦]

6楼的还可以接受

[abc130314]

b[0]=(byte)(0xff & (i >> 24))
b[1]=(byte)(0xff & (i >> 16))
b[2]=(byte)(0xff & (i >> 8))
b[3]=(byte)(0xff & i)

[notlogin]

不会 再看看其他答案