C++沉思录里的代码，不知道错在哪里？我抄错了？

[cuiniu1988]

#include<iostream>
using namespace std;

template<class T>
class Array
{
public:
Array():data(0),zs(0){}
Array(unsigned size):sz(size),data(new T[size]){}
~Array(){delete []data;}

const T& operator[](unsigned n) const
{
if(n >= sz || data == 0)
throw "Array subscript out of range";
return data[n];
}

T& operator[](unsigned n)
{
if(n >= sz || data == 0)
throw "Array subscript out of range";
return data[n];
}


operator T*()
{
return data;
}

operator const T* () const
{
return data;
}
private:
T* data;
unsigned sz;
Array(const Array& a);
Array& operator= (const Array);
};

void main()
{
Array<int> a(3);
a[0] = 0;
a[1] = 1;
a[2] = 2;
cout<<a[2]<<endl;

}

=============================================================
vs2008报很多错

[zhao19851019]

牛啊，高手

[sallan]

楼上看得很仔细阿

[needle2]

不懂，帮顶

[cattycat]

按1楼那个改一下吧，应该是写错了。
其他的错误，可能是a[]的时候，重载的运算符不能确定调用哪一个了，至少const T& operator []和T& operator[]是不能区分的。

[chainyu]

scott大师教导我们要离operator隐式类型转换远一些

#include<iostream>
using namespace std;

template<class T>
class Array
{
public:
	Array():data(0),sz(0) { }
	Array(unsigned size):data(new T[size]), sz(size) { }
	virtual ~Array() { delete [] data; }

	const T& operator[](const unsigned n) const
	{
		if(n >= sz || data == 0)
			throw "Array subscript out of range";
		return data[n];
	}

	T& operator[](const unsigned n)
	{
		if(n >= sz || data == 0)
			throw "Array subscript out of range";
		return data[n];
	}


	operator T*()
	{  
		return data;  
	}

	operator const T*() const
	{
		return data;
	}

private:
	T* data;
	unsigned sz;
	Array(const Array& a);
	Array& operator= (const Array);
};

int main()
{
	Array<int> Retry(3);

	Retry[(unsigned)0] = 0;
	Retry[(unsigned)1] = 1;
	Retry[(unsigned)2] = 2;
	cout<<Retry[(unsigned)2]<<endl;

	return 0;

}

[wesleyluo]

楼上的解释下呗。

[brookmill]

Array():data(0),zs(0){}
改成sz

[niejimaoo]

细心细心

[cuiniu1988]

我太粗心了，谢谢楼上各位了。