简单gridview中控件传值问题，在线等，解决问题可以再加

[zjj1211]

我在gridview里面放了一个LinkButton，在Click事件里我通过这样

 CommandArgument=<%# Eval("N_title")%>

LinkButton lb = (LinkButton)sender;  string tetle = lb.CommandArgument;

可以得到点击的那一条记录的一个字段N_title，但是现在我的事件中需要这一条记录的2个字段，
我又不想通过一个字段去数据库里查找另一个，有什么办法可以实现呢？

[PandaIT]

CommandArgument='<%# Eval("值一")+","+Eval("值二") %>'


取出来用split(',')

[wuyq11]

protected void LinkButton1_Click(object sender, EventArgs e)
{
LinkButton btn = sender as LinkButton;
GridViewRow row = btn.NamingContainer as GridViewRow;
GridView grd = row.NamingContainer as GridView;
TextBox txt=row.FindControl("TextBox1") as TextBox;
int id = (int)grd.DataKeys[row.RowIndex].Value;
}

[zjj1211]

[Quote=引用 2 楼 wuyq11 的回复:]
protected void LinkButton1_Click(object sender, EventArgs e)
{
LinkButton btn = sender as LinkButton;
GridViewRow row = btn.NamingContainer as GridViewRow;
GridView grd = row.NamingCon……
[/Quote]
TextBox txt=row.FindControl("TextBox1") as TextBox;
这句话没有用吧？

[天涯独行]

LinkButon btn=(LinkButton)sender;
GridViewRow gvr=(GridViewrow)btn.NamingContainer;
long id=Convert.ToInt64a(GridView1.DataKeys[gvr.RowIndex]["字段"].ToString()
long Number=Convert.ToInt64(((LinkButton)sender).CommandArgument.ToString());

[koukoujiayi]

    protected void LinkButton1_Click(object sender, EventArgs e)
    {
        LinkButton myL = (LinkButton)sender;
        int Index = ((GridViewRow)(myL.NamingContainer)).RowIndex;//获得行号
        string f1=((Label)GridView1.Rows[Index].Cells[列号1].FindControl("字段1id")).Text;//找字段1
        string f2=((Label)GridView1.Rows[Index].Cells[列号2].FindControl("字段2id")).Text;//找字段2
    }

[zjj1211]

[Quote=引用 5 楼 koukoujiayi 的回复:]
C# code
protected void LinkButton1_Click(object sender, EventArgs e)
{
LinkButton myL = (LinkButton)sender;
int Index = ((GridViewRow)(myL.NamingContainer)).RowIndex;//获得行号……
[/Quote]
不好意思 结过贴了 下次多给您的分