ajax 登录,谢谢!
用ajax提交form后,为什么不自动跳转到登陆成功页面???
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<script language="javascript">
function saveUserInfo()
{
//获取表单对象和用户信息值
var f = document.user_info;
var userName = f.user_name.value;
var userPass = f.user_pass.value;
//接收表单的URL地址
var url = "http://x.x.x.x/login.jsp? user_name="+ userName +"&password="+ userPass ;
//实例化Ajax
//var ajax = InitAjax();
var ajax = false;
//开始初始化XMLHttpRequest对象
if(window.XMLHttpRequest) { //Mozilla 浏览器
ajax = new XMLHttpRequest();
if (ajax.overrideMimeType) {//设置MiME类别
ajax.overrideMimeType("text/xml");
}
}
else if (window.ActiveXObject) { // IE浏览器
try {
ajax = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
ajax = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {}
}
}
if (!ajax) { // 异常,创建对象实例失败
window.alert("不能创建XMLHttpRequest对象实例.");
return false;
}
//通过get方式打开连接
ajax.open("GET", url, true);
ajax.send(null);
//获取执行状态
ajax.onreadystatechange = function() {
//如果执行状态成功,那么就把返回信息写到指定的层里
if (ajax.readyState == 4 && ajax.status == 200) {
}
}
}
</script>
<body >
<div id="msg"></div>
<form name="user_info" method="GET" action="">
姓名:<input type="text" name="user_name" /><br />
密码:<input type="text" name="user_pass" /><br />
<input type="button" value="提交表单" onClick="saveUserInfo()">
</form>
</body>