如何获取一个月里连续3天Flag为2的记录

[angelcool]

如何获取一个月里连续3天Flag为2的记录。

table_06（6月的表格）定义如下：
ID
Flag
Date（日期，仅包含1-31，类型为字符串）
。。。


ID Flag Date
232 1 1
232 2 2
232 1 3
233 4 2
233 2 3
233 3 4
dff 1 7


希望得到的结果是：

ID Count
233 3

搜到一个类似的，但这个是Oracle的，我的数据库是Sybase，无法执行。
应该怎样修改呢？或者应该怎样实现？

select ID,count(1) from (
select * from
(select ID,Date,cnt,lag(Date,1,Date-1) over(partition by ID order by rownum) last from table_06)
where Date=last+1)
group by ID having count(1)>=3

[angelcool]

to htl258


运行了快一个小时了，可还没出结果？？
好像语句有什么问题呀！！

[TheGodOfGods]

233只有连续两天吧flag为2吧。lz出错题了

[htl258_Tony]

描述与结果不相对吧。

[Mr_Nice]

ID Flag Date
232 1 1
232 2 2
232 1 3
233 4 2
233 2 3
233 3 4
dff 1 7

里面没有连续3天flag = 2的阿？

[htl258_Tony]

--> 生成测试数据表: [tb]
IF OBJECT_ID('[tb]') IS NOT NULL
	DROP TABLE [tb]
GO
CREATE TABLE [tb] ([ID] [nvarchar](10),[Flag] [int],[Date] [int])
INSERT INTO [tb]
SELECT '232','1','1' UNION ALL
SELECT '232','2','2' UNION ALL
SELECT '232','1','3' UNION ALL
SELECT '233','4','2' UNION ALL
SELECT '233','2','3' UNION ALL
SELECT '233','3','4' UNION ALL
SELECT 'dff','1','7'


-->SQL查询如下:

SELECT ID, COUNT(1) cnt 
FROM [tb] t
WHERE EXISTS(
          SELECT 1 
          FROM tb
          WHERE id = t.id
          	AND flag = 2
      )
	AND EXISTS(
	        SELECT 1 
	        FROM tb
	        WHERE id = t.id
	        	AND (date=t.date+1 OR date=t.date-1)
	    )
GROUP BY ID

/*
ID         cnt
---------- -----------
232        3
233        3

(2 行受影响)
*/

[htl258_Tony]

-->加个大于等于三天的条件:

SELECT ID, COUNT(1) cnt 
FROM [tb] t
WHERE EXISTS(
          SELECT 1 
          FROM tb
          WHERE id = t.id
          	AND flag = 2
      )
	AND EXISTS(
	        SELECT 1 
	        FROM tb
	        WHERE id = t.id
	        	AND (date=t.date+1 OR date=t.date-1)
	    )
GROUP BY ID
HAVING COUNT(1)>=3

/*
ID         cnt
---------- -----------
232        3
233        3

(2 行受影响)
*/

[永生天地]

[Quote=引用楼主 angelcool 的回复:]
我的数据库是Sybase

[/Quote]

帮顶，可再发到sybase里问问

[Mr_Nice]

--> 测试数据：[TB]
if object_id('[TB]') is not null drop table [TB]
create table [TB]([ID] varchar(3),[Flag] int,[Date] int)
insert [TB]
select '232',1,1 union all
select '232',2,2 union all
select '232',1,3 union all
select '233',2,2 union all
select '233',2,3 union all
select '233',2,4 union all
select 'dff',1,7

select * from [TB]




;WITH TT
AS(
SELECT id,flag,date, [rowid]=ROW_NUMBER()OVER (PARTITION BY id ORDER BY date) FROM TB WHERE flag = 2)

SELECT id,cnt = COUNT(1)
FROM (
SELECT * FROM TT WHERE date = rowid+1
)A
GROUP BY id HAVING COUNT(1)>=3

/*id   cnt
---- -----------
233  3

(1 行受影响)*/

[angelcool]

to xys_777
在Sybase开贴了，但等了一天都没人回答，才在这里开贴的。


to TheGodOfGods
是我的失误，233的Flag值应均大于3

[chuifengde]

--ID相同且连续三天或三天以上Flag值大于等于2的ID及数量 
declare @a table(ID INT, Flag INT, Date INT)
INSERT @a SELECT 232, 1, 1
union all select 232 ,2, 2   
union all select 232 ,1, 3
union all select 233, 4, 2
union all select 233, 2, 3
union all select 233, 3, 4
union all select 333, 1, 7

SELECT id,COUNT(date-o) [COUNT] FROM 
(
	SELECT * ,o=(SELECT COUNT(1)+1 FROM @a WHERE id=a.id AND date<a.date AND flag>=2)
	FROM @a a 
	WHERE flag>=2
)aa
GROUP BY id,date-o
HAVING COUNT(date-o)>2
--result
/*
id          COUNT       
----------- ----------- 
233         3

（所影响的行数为 1 行）

*/

[htl258_Tony]

[Quote=引用 8 楼 angelcool 的回复:]
to xys_777
在Sybase开贴了，但等了一天都没人回答，才在这里开贴的。


to TheGodOfGods
是我的失误，233的Flag值应均大于3
[/Quote]

楼主，这就是你的不对了

[htl258_Tony]

--> 生成测试数据表: [tb]
IF OBJECT_ID('[tb]') IS NOT NULL
	DROP TABLE [tb]
GO
CREATE TABLE [tb] ([ID] [nvarchar](10),[Flag] [int],[Date] [int])
INSERT INTO [tb]
SELECT '232','1','1' UNION ALL
SELECT '232','2','2' UNION ALL
SELECT '232','1','3' UNION ALL
SELECT '233','4','2' UNION ALL
SELECT '233','2','3' UNION ALL
SELECT '233','3','4' UNION ALL
SELECT 'dff','1','7'


-->SQL查询如下:

SELECT ID, COUNT(1) cnt 
FROM [tb] t
WHERE EXISTS(
          SELECT 1 
          FROM tb
          WHERE id = t.id
          	AND flag >= 3
      )
	AND EXISTS(
	        SELECT 1 
	        FROM tb
	        WHERE id = t.id
	        	AND (date=t.date+1 OR date=t.date-1)
	    )
GROUP BY ID
HAVING COUNT(1)>=3

/*
ID         cnt
---------- -----------
233        3

(1 行受影响)
*/

[老黎]

赛贝斯，不懂

[angelcool]

to htl258

AND EXISTS(
SELECT 1
FROM tb
WHERE id = t.id
AND (date=t.date+1 OR date=t.date-1)

好像只能保证当前记录前后有一条记录Flag>=3，
而且我现在要求查询连续10天Flag>=3，好像就不行了呀！！

[chuifengde]

[Quote=引用 13 楼 angelcool 的回复:]
to htl258

AND EXISTS(
SELECT 1
FROM tb
WHERE id = t.id
AND (date=t.date+1 OR date=t.date-1)

好像只能保证当前记录前后有一条记录Flag>=3，
而且我现在要求查询连续10天Flag>=3，好像就不行了呀！！
[/Quote]
看9楼把count()>2改成count()>9 flag>2 改成flag>3

[htl258_Tony]

[Quote=引用 13 楼 angelcool 的回复:]
to htl258

AND EXISTS(
SELECT 1
FROM tb
WHERE id = t.id
AND (date=t.date+1 OR date=t.date-1)

好像只能保证当前记录前后有一条记录Flag>=3，
而且我现在要求查询连续10天Flag>=3，好像就不行了呀！！
[/Quote]
改HAVING的：

SELECT ID, COUNT(1) cnt 
FROM [tb] t
WHERE EXISTS(
          SELECT 1 
          FROM tb
          WHERE id = t.id
              AND flag >= 3
      )
    AND EXISTS(
            SELECT 1 
            FROM tb
            WHERE id = t.id
                AND (date=t.date+1 OR date=t.date-1)
        )
GROUP BY ID
HAVING COUNT(1)>=10