select distinct 疑问

[junlintianxia07]

SELECT distinct 单据号, 个人编号, SUM(总费用) AS 总费用, SUM(补偿金额) AS 补偿总费用,
SUM(其它补偿) AS 其它补偿,政策年度,补偿年度,单据日期
FROM dbo.v_apprexpense
WHERE GROUP BY 单据号,个人编号, 政策年度,补偿年度,业务类型,单据日期

我现在想要得到结果 单据号 不重复的 结果集，为什么加上distinct 不起作用，
我应该如何修改这个sql 呢？
谢谢！

[nightmaple]

得出的结果是 按照单据号字段distinct，还是所有字段？
我想按照所有字段distinct ，如何写？
---------------------------------------------

是按所有字段的~

在前面国distinct就行了~

[claro]

鼓掌！

这帖很热！

[永生天地]

SELECT 
单据号, 
个人编号, 
SUM(总费用) AS 总费用, 
SUM(补偿金额) AS 补偿总费用,
SUM(其它补偿) AS 其它补偿,
政策年度,
补偿年度,
单据日期
FROM (select distinct * from dbo.v_apprexpense) v_apprexpense -----加个别名，对后面没有影响
WHERE ....
GROUP BY 单据号,个人编号, 政策年度,补偿年度,业务类型,单据日期

[请叫我潇洒哥]

学习

[ws_hgo]

用not exists

[ws_hgo]

个人编号是唯一的吗？

[bancxc]

distinct 是去除整行重复的

[东那个升]

去掉distinct

[junlintianxia07]

出来的结果集里面 好多单据编码为重复的记录，想求 单据编码 一条 就显示 一条记录，不允许重复单据编码，其他的是 根据条件出来的 字段 ，个人编码 有时候会重复，但是 单据编码不允许重复！坐等高人出现！！！！！！在线结贴

[永生天地]

处理表重复记录(查询和删除) 收藏 
--处理表重复记录(查询和删除)
/******************************************************************************************************************************************************
1、Num、Name相同的重复值记录,没有大小关系只保留一条
2、Name相同,ID有大小关系时,保留大或小其中一个记录
整理人：中国风(Roy)

日期:2008.06.06
******************************************************************************************************************************************************/

--1、用于查询重复处理记录(如果列没有大小关系时2000用生成自增列和临时表处理,SQL2005用row_number函数处理)

--> --> (Roy)生成測試數據

if not object_id('Tempdb..#T') is null
    drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go


--I、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时，效率高于1、2
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)

方法2:
select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID

方法3:
select * from #T a where ID=(select min(ID) from #T where Name=a.Name)

方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 

方法5:
select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)

方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0

方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)

方法8:
select * from #T a where ID!>all(select ID from #T where Name=a.Name)

方法9(注:ID为唯一时可用):
select * from #T a where ID in(select min(ID) from #T group by Name)

--SQL2005:

方法10:
select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID

方法11:

select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1

生成结果:
/*
ID          Name Memo
----------- ---- ----
1           A    A1
4           B    B1

(2 行受影响)
*/


--II、Name相同ID最大的记录,与min相反:
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID>a.ID)

方法2:
select a.* from #T a join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID order by ID

方法3:
select * from #T a where ID=(select max(ID) from #T where Name=a.Name) order by ID

方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID<=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 

方法5:
select * from #T a group by ID,Name,Memo having ID=(select max(ID)from #T where Name=a.Name)

方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)=0

方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID desc)

方法8:
select * from #T a where ID!<all(select ID from #T where Name=a.Name)

方法9(注:ID为唯一时可用):
select * from #T a where ID in(select max(ID) from #T group by Name)

--SQL2005:

方法10:
select ID,Name,Memo from (select *,max(ID)over(partition by Name) as MinID from #T a)T where ID=MinID

方法11:
select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID desc) as MinID from #T a)T where MinID=1

生成结果2:
/*
ID          Name Memo
----------- ---- ----
3           A    A3
5           B    B2

(2 行受影响)
*/



--2、删除重复记录有大小关系时,保留大或小其中一个记录


--> --> (Roy)生成測試數據

if not object_id('Tempdb..#T') is null
    drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go

--I、Name相同ID最小的记录(推荐用1,2,3),保留最小一条
方法1:
delete a from #T a where  exists(select 1 from #T where Name=a.Name and ID<a.ID)

方法2:
delete a  from #T a left join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null

方法3:
delete a from #T a where ID not in (select min(ID) from #T where Name=a.Name)

方法4(注:ID为唯一时可用):
delete a from #T a where ID not in(select min(ID)from #T group by Name)

方法5:
delete a from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)>0

方法6:
delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID)

方法7:
delete a from #T a where ID>any(select ID from #T where Name=a.Name)



select * from #T

生成结果:
/*
ID          Name Memo
----------- ---- ----
1           A    A1
4           B    B1

(2 行受影响)
*/


--II、Name相同ID保留最大的一条记录:

方法1:
delete a from #T a where  exists(select 1 from #T where Name=a.Name and ID>a.ID)

方法2:
delete a  from #T a left join (select max(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID where b.Id is null

方法3:
delete a from #T a where ID not in (select max(ID) from #T where Name=a.Name)

方法4(注:ID为唯一时可用):
delete a from #T a where ID not in(select max(ID)from #T group by Name)

方法5:
delete a from #T a where (select count(1) from #T where Name=a.Name and ID>a.ID)>0

方法6:
delete a from #T a where ID<>(select top 1 ID from #T where Name=a.name order by ID desc)

方法7:
delete a from #T a where ID<any(select ID from #T where Name=a.Name)


select * from #T
/*
ID          Name Memo
----------- ---- ----
3           A    A3
5           B    B2

(2 行受影响)
*/





--3、删除重复记录没有大小关系时，处理重复值


--> --> (Roy)生成測試數據

if not object_id('Tempdb..#T') is null
    drop table #T
Go
Create table #T([Num] int,[Name] nvarchar(1))
Insert #T
select 1,N'A' union all
select 1,N'A' union all
select 1,N'A' union all
select 2,N'B' union all
select 2,N'B'
Go

方法1:
if object_id('Tempdb..#') is not null
    drop table #
Select distinct * into # from #T--排除重复记录结果集生成临时表#

truncate table #T--清空表

insert #T select * from #    --把临时表#插入到表#T中

--查看结果
select * from #T

/*
Num         Name
----------- ----
1           A
2           B

(2 行受影响)
*/

--重新执行测试数据后用方法2
方法2:

alter table #T add ID int identity--新增标识列
go
delete a from  #T a where  exists(select 1 from #T where Num=a.Num and Name=a.Name and ID>a.ID)--只保留一条记录
go
alter table #T drop column ID--删除标识列

--查看结果
select * from #T

/*
Num         Name
----------- ----
1           A
2           B

(2 行受影响)

*/

--重新执行测试数据后用方法3
方法3:
declare Roy_Cursor cursor local for
select count(1)-1,Num,Name from #T group by Num,Name having count(1)>1
declare @con int,@Num int,@Name nvarchar(1)
open Roy_Cursor
fetch next from Roy_Cursor into @con,@Num,@Name
while @@Fetch_status=0
begin 
    set rowcount @con;
    delete #T where Num=@Num and Name=@Name
    set rowcount 0;
    fetch next from Roy_Cursor into @con,@Num,@Name
end
close Roy_Cursor
deallocate Roy_Cursor

--查看结果
select * from #T
/*
Num         Name
----------- ----
1           A
2           B

(2 行受影响)
*/



本文来自CSDN博客，转载请标明出处：http://blog.csdn.net/htl258/archive/2009/04/16/4083040.aspx

[永生天地]

试试这个

SELECT  单据号, 个人编号, SUM(总费用) AS 总费用, SUM(补偿金额) AS 补偿总费用,
  SUM(其它补偿) AS 其它补偿,政策年度,补偿年度,单据日期
FROM dbo.v_apprexpense t
WHERE  (select count(1) from dbo.v_apprexpense where 单据号=t.单据号)=1
GROUP BY 单据号,个人编号, 政策年度,补偿年度,业务类型,单据日期

[qilinshu]

楼主这样用是不行的，因为你distinct后面跟的字段太多。只要其中有一个字段是不重复的，你很多数据照样会显示出来。例如“补偿年度”字段不重复，但是“单据号”有重复的情况，这种记录照样会都呈现出来。你要呈现不重复的“单据号”就不可能实现。

[junlintianxia07]

SELECT 单据号, 个人编号, SUM(总费用) AS 总费用, SUM(补偿金额) AS 补偿总费用,
SUM(其它补偿) AS 其它补偿,政策年度,补偿年度,单据日期
FROM dbo.v_apprexpense
WHERE GROUP BY 单据号,个人编号, 政策年度,补偿年度,业务类型,单据日期


这是原始sql ，在这个基础上面 改，如何改，我不想要单据号重复的记录
单据号 个人编号， 总费用
001 1234 1000.11
001 1234 1000.11
002 4567 100.05
得到这样的结果

单据号 个人编号， 总费用
001 1234 1000.11
002 4567 100.05

[linjunf]

你都分组了 还怎么有用
你要不就用分组 要不就用distinct

[linjunf]

SELECT 单据号, 个人编号, SUM(总费用) AS 总费用, SUM(补偿金额) AS 补偿总费用,
SUM(其它补偿) AS 其它补偿,政策年度,补偿年度,单据日期
FROM dbo.v_apprexpense
WHERE GROUP BY 单据号


SELECT distinct 单据号, 个人编号, SUM(总费用) AS 总费用, SUM(补偿金额) AS 补偿总费用,
SUM(其它补偿) AS 其它补偿,政策年度,补偿年度,单据日期
FROM dbo.v_apprexpense

[junlintianxia07]

[Quote=引用 11 楼 linjunf 的回复:]
SELECT 单据号, 个人编号, SUM(总费用) AS 总费用, SUM(补偿金额) AS 补偿总费用,
SUM(其它补偿) AS 其它补偿,政策年度,补偿年度,单据日期
FROM dbo.v_apprexpense
WHERE GROUP BY 单据号


SELECT distinct 单据号, 个人编号, SUM(总费用) AS 总费用, SUM(补偿金额) AS 补偿总……
[/Quote]
这样更不对了， 那些没有聚合函数的，不用group by 包起来 不行的

[junlintianxia07]

[Quote=引用 7 楼 xys_777 的回复:]
试试这个


SQL code
SELECT 单据号, 个人编号, SUM(总费用) AS 总费用, SUM(补偿金额) AS 补偿总费用,
SUM(其它补偿) AS 其它补偿,政策年度,补偿年度,单据日期
FROM dbo.v_apprexpense t
WHERE (select count(1) from dbo.v_apprexpense where 单据号=t.单据……
[/Quote]


这个表dbo.v_apprexpense 不能重命名，后面程序要用表名称啊

[v1ctory1216]

distinct和group by 一起用没什么意义

[linjunf]

[Quote=引用 12 楼 junlintianxia07 的回复:]
引用 11 楼 linjunf 的回复:
SELECT 单据号, 个人编号, SUM(总费用) AS 总费用, SUM(补偿金额) AS 补偿总费用,
SUM(其它补偿) AS 其它补偿,政策年度,补偿年度,单据日期
FROM dbo.v_apprexpense
WHERE GROUP BY 单据号


SELECT distinct 单据号, 个人编号, SUM(总费用) AS 总……
[/Quote]

确实 只看了分组和distinct 没想那么多
看来要分2步走 先剔除重复再聚合函数

[bycz123456]

[Quote=引用 10 楼 linjunf 的回复:]
你都分组了 还怎么有用
你要不就用分组 要不就用distinct
[/Quote]

同意。