js如何获取treeview选中节点的值

[nbzsg]

js如何获取treeview选中节点的值, 在通过按钮确认吧选中的值传在另外一个页面

请问谁有JS获取treeview选中节点好方法，急用， 谢谢

[LovingAlison]

我曾经试着JS遍历过treeview 遍历出来的就没有那个层次结构了

[LovingAlison]

点击treeview 的treenode后 肯定要触发后台代码的

建议你用下iframe好了

[wuyq11]

<asp:TreeView ID="TreeView1" runat="server" onclick="javascript:client_OnTreeNodeChecked();" NodeIndent="10" ShowCheckBoxes="All" ShowLines="True">
function checkParent (obj)
{
while(obj != null)
{
var tagName = obj.tagName.toLowerCase();
if(tagName == "div" && obj.id == "TreeView1")
{
return;
}

if(tagName == "table")
{
var checkBox = obj.getElementsByTagName("INPUT");
if(checkBox.length >0)
{
checkBox[0].checked = true;
}
obj = obj.parentElement.previousSibling;
}
else
obj = obj.parentElement;
}
}

function client_OnTreeNodeChecked()
{
var obj = window.event.srcElement;
var treeNodeFound = false;
var checkedState;
if (obj.tagName == "INPUT" && obj.type == "checkbox")
{
var treeNode = obj;
checkedState = treeNode.checked;

if(checkedState)
{
checkParent(obj);
}

do
{
obj = obj.parentElement;
}
while (obj.tagName != "TABLE")

var parentTreeLevel = obj.rows[0].cells.length;
var parentTreeNode = obj.rows[0].cells[0];

var tables = obj.parentElement.getElementsByTagName("TABLE");
var numTables = tables.length
if (numTables >= 1)
{
for (i=0; i < numTables; i++)
{
if(tables[i] == obj)
{
treeNodeFound = true;
i++;
if(i == numTables)
{
return;
}
}
if (treeNodeFound == true)
{
var childTreeLevel = tables[i].rows[0].cells.length;
if (childTreeLevel > parentTreeLevel)
{
var cell = tables[i].rows[0].cells[childTreeLevel - 1];
var inputs = cell.getElementsByTagName("INPUT");
inputs[0].checked = checkedState;
}
else
{
return;
}
}
}
}
}
}
http://topic.csdn.net/u/20100524/17/6f38c355-6f99-49b5-8e62-2bcb2dc72385.html

[huihuiworf]

[Quote=引用 3 楼 wuyq11 的回复:]
<asp:TreeView ID="TreeView1" runat="server" onclick="javascript:client_OnTreeNodeChecked();" NodeIndent="10" ShowCheckBoxes="All" ShowLines="True">
function checkParent (obj)
{
while(obj != ……
[/Quote]
不错，支持了。

[nbzsg]

这个还是不可以用呀， 可以给个例子吗

[nbzsg]

谢谢 不错