程序修改密码失败，还是老样子，哪里错了？

cph1737 2010-07-20 01:00:32

<?php
session_start();
include("global.php");
include("conn.php");
$id=$_GET['id'];
$sql="select * from `user` where `id`='$id'";
$rs=mysql_query($sql);
$row=mysql_fetch_array($rs);
$user=$row[user];

if(isset($_POST[btn1])){
$pwd=$_POST[pwd];
$sql="update `user` set `pwd`='$pwd' where `id`='$id'";
$rs=mysql_query($sql);
echo "<script>alert('修改成功！');location.href='user_list.php';</script>";
}
?>
<html>
<head>
<title></title>
</head>
<script language="javascript">
function check(){
if(document.edit_pass.pwd.value==""){
alert("密码不能为空!");
document.edit_pass.pwd.focus();
return false;
}
if(document.edit_pass.repwd.value==""){
alert("请在输一次密码!");
document.edit_pass.repwd.focus();
return false;
}
if(document.edit_pass.pwd.value!=document.edit_pass.repwd.value){
alert("两次密码输入不一致！");
document.edit_pass.repwd.focus();
return false;
}
}
</script>
<body>
<div class="top"><b>修改密码</b></div>

<center>
<table border="1">
<tr>
<td>用户名</td>
<td><?php echo $user?></td>
</tr>
<form method="post" action="edit_pass.php" name="edit_pass" onsubmit="return check()">
<tr>
<td>新密码</td>
<td><input type="text" name="pwd" size="30"></td>
</tr>
<tr>
<td>重输密码</td>
<td><input type="text" name="repwd" size="30"></td>
</tr>
<tr align="center">
<td colspan="2"><input type="submit" name="btn1" value="修改"> <input type="reset" name="btn2" value="取消"></td>
</tr>
</table>
</center>
</form>
</body>
</html>
这个程序是用来修改密码的，为什么不能修改密码，哪里错了，请各位高手相助！

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cph1737 2010-07-20

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[Quote=引用 1 楼 kyzy_yy_pm 的回复:]
echo update `user` set `pwd`='$pwd' where `id`='$id';
输出的是什么
[/Quote]
echo 出来没有传ID，在form中加一个隐藏域，在传ID就OK了

amani11 2010-07-20

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<form method="post" action="edit_pass.php" name="edit_pass" onsubmit="return check()">

改成

<form method="post" action="edit_pass.php?id=<?php echo $id;?>" name="edit_pass" onsubmit="return check()">

试试

CunningBoy 2010-07-20

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<?php

session_start();

include("global.php");

include("conn.php");

$id=$_GET['id'];

$sql="select * from `user` where `id`='$id'";

//要先连接数据库

$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');

//选择数据库

$db_selected = mysql_select_db('yourdatabase', $link);

$rs=mysql_query($sql);

$row=mysql_fetch_array($rs);

$user=$row[user];



if(isset($_POST[btn1])){

	$pwd=$_POST[pwd];

	$sql="update `user` set `pwd`='$pwd' where `id`='$id'";

	$rs=mysql_query($sql);

	echo "<script>alert('修改成功！');location.href='user_list.php';</script>";

}

?>

<html>

<head>

<title></title>

</head>

<script language="javascript">

function check(){

if(document.edit_pass.pwd.value==""){

alert("密码不能为空!");

document.edit_pass.pwd.focus();

return false;

}

if(document.edit_pass.repwd.value==""){

alert("请在输一次密码!");

document.edit_pass.repwd.focus();

return false;

}

if(document.edit_pass.pwd.value!=document.edit_pass.repwd.value){

alert("两次密码输入不一致！");

document.edit_pass.repwd.focus();

return false;

}

}

</script>

<body>

<div class="top"><b>修改密码</b></div>

<center>

<table border="1">

	<tr>

		<td>用户名</td>

		<td><?php echo $user?></td>

	</tr>

	<form method="post" action="edit_pass.php" name="edit_pass" onsubmit="return check()">

	<tr>

		<td>新密码</td>

		<td><input type="text" name="pwd" size="30"></td>

	</tr>

	<tr>

		<td>重输密码</td>

		<td><input type="text" name="repwd" size="30"></td>

	</tr>

	<tr align="center">

		<td colspan="2"><input type="submit" name="btn1" value="修改">  <input type="reset" name="btn2" value="取消"></td>

	</tr>



</table>

</center>

</form>

</body>

</html>

?>

总哈哈 2010-07-20

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楼主，你的有些代码级别停留在php4，请买一本php5的书好好的看一下。
$sql="update `user` set `pwd`='$pwd' where `id`='$id'";
echo "///" . $sql . "///";
$rs=mysql_query($sql);
请把///这里的语句贴出来看看！///

kyzy_yy_pm 2010-07-20