求一正则表达式

[oyjqdlp364356378]

假如一文件中有包含以下

$actionMaps = array(
................,
................,
);

字符串,如何把该字符串匹配出来~``

[oyjqdlp364356378]

里面的....不是.是省略符号~```

[oyjqdlp364356378]

$actionMaps = array(

'list' => 'ListAction',
'view' => 'ViewAction',
...,

);

相当于就是把array里面的数据提取出来~`

[oyjqdlp364356378]

没人先顶顶~`

[CunningBoy]

<?php
$subject = file_get_contents('yourfilename');
preg_match_all('/\$actionMaps = array\(.*\);/is', $subject, $matches);
print_r($matches);
?>

[amani11]

代码最好多一些，这种方法，数组中间如果内容如果有字符串);就完蛋了


如果字符串符合php语法，可以考虑include这个文件，然后将数组打印出来

$str	= 'asdfas^……
$actionMaps = array(
................,
................,
);
^!@#@!#!
';
echo preg_match_all('/\$actionMaps = array\((.*?)\);/is', $str, $match);

print_r($match[0]);

[Dleno]

$str='
$a="432435";
$actionMaps = array(
0=>array(
0=>"123",
"a"=>"abc",
),
1=>array(
0=>"123",
"a"=>"abc",
),
);
//gfdgfdgdfgd
$actionMaps1 = array(
0=>"123",
"a"=>"abc",
);
$fsfs=54353;
//543535
';
preg_match_all('~(\$[a-zA-z0-9_]+\s?=\s?array\([^;]*?\);)~is',$str,$data);
print_r($data[0]);

[phpboy]

$str = '
$actionMaps = array(
	................,
	................,
);
';

preg_match('/\$actionmaps.*?\);/is', $str, $match);

print_r($match);