模板问题 请教 有点搞不懂了！

[xengine-qyt]

#include <iostream>
using namespace std;

template<class T,int n>  
class people
{
public:
 people();
 people(const T&t);
 T &operator[](int i);
 void Show();
private:
 T a[n];

};
template<class T,int n>
people<T,n>::people()
{
 cout<<"执行构造函数\n";
 for(int i = 0;i < n;i++)
 {
  a[i] = (i + 1);
 }
}
template<class T,int n>
people<T,n>::people(const T&t)
{
 cout<<"执行带一个参数的构造函数\n";
 for (int i = 0;i < n;i++)
 {
  a[i] = t;
 }
}
template<class T,int n>
T &people<T,n>::operator[](int i)
{
 cout<<"执行下标运算符函数 opeartor[]\n";
 if (i < 0||i >= n)
 {
  cerr<<"超出数组限制，第："<<i<<"个元素溢出\n";
  exit(EXIT_FAILURE);
 }
 return a[i];
}
template<class T,int n>
void people<T,n>::Show()
{
 for (int i = 0;i < n;i++)
 {
  cout<<"a["<<i<<"]:"<<a[i]<<"\t";
 }
 cout<<endl;
}
int main()
{
 people<double,4>one;
 one.Show();
 people<double,4> *p = new people<double,4>[4];
 for (int i = 0;i < 9;i++)
 {
  p[i] = one[i];//这里将会调用到T &people<T,n>::operator[](int i) 
  p[i].Show();
 }
 return 0;
}
int main()
{
 people<people<int,2>,3>two;
 int obj = 1;
 for (int i = 0;i < 4;i++)
 {
  int sum = 1;
  for (int j = 0;j < 2; j++)
  {
   cout<<"\ntwo["<<i<<"]["<<j<<"]:"<<two[i][j]<<"\n";
   cout<<"第"<<sum++<<"个元素输出完毕\n\n";
  }
  cout<<"第"<<obj++<<"个对象中的数组元素输出完毕\n\n";
 }
 return 0;
} 

看上面的代码，请帮忙解释下 two[i][j] 这个是如何得到 1的 第一次循环的时候。帮忙吧流程说清楚，谢谢 不太明白 我新手！！

[weixiaoshashou]

怎么又两个main()函数

[xengine-qyt]

int main()
{
people<double,4>one;
one.Show();
people<double,4> *p = new people<double,4>[4];
for (int i = 0;i < 9;i++)
{
p[i] = one[i];//这里将会调用到T &people<T,n>::operator[](int i)
p[i].Show();
}
return 0;
}
这个是多余的 ！

[Qlaiaqu]

#include <iostream>

using namespace std;

template<class T,int n>  
class people
{
public:
	people();
	people(const T&t);
	T &operator[](int i);
	void Show();
private:
	T a[n];

};
template<class T,int n>
people<T,n>::people()
{
	cout<<"执行构造函数\n";
	for(int i = 0;i < n;i++)
	{
		a[i] = (i + 1);//2.调用拷贝构造函数
	}
}
template<class T,int n>
people<T,n>::people(const T&t)
{
	cout<<"执行带一个参数的构造函数\n";
	for (int i = 0;i < n;i++)//3.赋值，对象类似于二维数组，分别是{1,1},{2,2},{3,3}
	{
		a[i] = t;
	}
}
template<class T,int n>
T &people<T,n>::operator[](int i)
{
	cout<<"执行下标运算符函数 opeartor[]\n";
	if (i < 0||i >= n)
	{
		cerr<<"超出数组限制，第："<<i<<"个元素溢出\n";
		exit(EXIT_FAILURE);
	}
	return a[i];//5.返回two[0],一个people<int,2>,再次进入此模板（生成的函数实例不一样），返回two[0][0]
}
template<class T,int n>
void people<T,n>::Show()
{
	for (int i = 0;i < n;i++)
	{
		cout<<"a["<<i<<"]:"<<a[i]<<"\t";
	}
	cout<<endl;
}


int main() 
{ 
	people<people<int,2>,3>two; //1.调用初始化函数
	int obj = 1; 
	for (int i = 0;i < 4;i++)
	{ 
		int sum = 1; 
		for (int j = 0;j < 2; j++)
		{ 
			cout<<"\ntwo["<<i<<"]["<<j<<"]:"<<two[i][j]<<"\n"; //4.two[0][0],调用people<int,2> &people<people<int,2>,3>::operator[](int i)，再调用int &people<int,2>::operator[](int i)
			cout<<"第"<<sum++<<"个元素输出完毕\n\n"; 
		} 
		cout<<"第"<<obj++<<"个对象中的数组元素输出完毕\n\n";
	} 
	return 0;
}

[alang512]

只有一个主函数的啊 ，我明白了 楼主是想定义 两个类对象。