请教高手，此SQL如何写？

[parss]

表tt中有两个字段,如下:

/*
AA     BB
11     0
11     2
11     2
11     3
11     2
11     2
11     2
11     1

*/

用sql统计: bb字段中连续出现的次数大于2, 并且BB字段中的值小于2的不计算
如表中第一条记录不记，第二条记录开始统计，到第四条记录时BB字段为3而上面统计过值为2的记录一共2条，
则不记。从第五条记录开始，到第七条记录值都为2,则记为1.

/*
--结果应该显示为：

AA    BB
---------
11     1
*/

[nightmaple]

没看懂~~~

[guguda2008]

游标或者UPDATE吧

[lg314]

没有主键吗?

[SQLCenter]

--> 测试数据：#
if object_id('tempdb.dbo.#') is not null drop table #
create table #(AA int, BB int)
insert into #
select 11, 0 union all
select 11, 2 union all
select 11, 2 union all
select 11, 3 union all
select 11, 2 union all
select 11, 2 union all
select 11, 2 union all
select 11, 1

; with a as
(
	select row=row_number()over(order by getdate()),* from #
),
b as
(
	select id=row-row_number()over(partition by bb order by row),* from a where BB>=2
)
select AA,BB=1 from b group by id,AA having count(1)>2

/*
AA          BB
----------- -----------
11          1
*/

[xman_78tom]

-- 表中的记录应该用 identity 列标示顺序，依赖存储顺序是不可靠的。
declare @tab table(aa int,bb int);
insert into @tab (aa,bb)
 select 11,0 union all select 11,2 union all
 select 11,2 union all select 11,3 union all
 select 11,2 union all select 11,2 union all
 select 11,2 union all select 11,1;

with t0 as(
select row_number() over (order by getdate()) id,aa,bb from @tab
),
t1 as(
select id,aa,bb,
id-ROW_NUMBER() over (partition by bb order by id) grp from t0
),
t2 as(
select id,aa,bb,count(1) over (partition by grp) cnt from t1
)
select aa,bb from t0
where id in (select max(id)+1 from t2
where cnt>2 and bb>=2);

[guguda2008]

UPDATE加个辅助列

IF OBJECT_ID('TB') IS NOT NULL DROP TABLE TB
GO
CREATE TABLE TB(AA INT,BB INT)
INSERT INTO TB
SELECT 11,     0 UNION ALL
SELECT 11,     2 UNION ALL
SELECT 11,     2 UNION ALL
SELECT 11,     3 UNION ALL
SELECT 11,     2 UNION ALL
SELECT 11,     2 UNION ALL
SELECT 11,     2 UNION ALL
SELECT 11,     1
GO
ALTER TABLE TB ADD CC INT
GO
DECLARE @AA INT,@BB INT,@CC INT
UPDATE TB SET @CC=CASE WHEN @AA=AA AND @BB=BB AND @BB>=2 THEN @CC+1 ELSE 1 END,@AA=AA,@BB=BB,CC=@CC

SELECT AA,COUNT(1) FROM TB 
WHERE CC=3
GROUP BY AA
/*
11	1
*/

[guguda2008]

加了ROW_NUMBER物理排序就乱了啊

[羽飞]

我也请教大侠们，顺序会一定吗？

[guguda2008]

[Quote=引用 5 楼 xman_78tom 的回复:]

SQL code

-- 表中的记录应该用 identity 列标示顺序，依赖存储顺序是不可靠的。
declare @tab table(aa int,bb int);
insert into @tab (aa,bb)
select 11,0 union all select 11,2 union all
select 11,2 union all select 11,3 union al……
[/Quote]
学习了。。。原来可以用GETDATE排序的。。。

[parss]

表中有一个creationtime（记录创建时间）,使用的是sqlserver2005

[百年树人]

---测试数据---
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([AA] int,[BB] int)
insert [tb]
select 11,0 union all
select 11,2 union all
select 11,2 union all
select 11,3 union all
select 11,2 union all
select 11,2 union all
select 11,2 union all
select 11,1
go
 
---查询---
;with josy as
(
select rn1=row_number() over(order by getdate()),* from tb
)
select a.AA,count(1) as BB
from
(select rn2=row_number() over(order by getdate()),* 
  from josy t 
  where not exists(select 1 from josy where bb=t.bb and rn1=t.rn1-1)
) a,
(select rn2=row_number() over(order by getdate()),* 
  from josy t 
  where not exists(select 1 from josy where bb=t.bb and rn1=t.rn1+1)
) b
where a.bb=b.bb and a.rn2=b.rn2 and b.rn1-a.rn1>=2
group by a.AA

---结果---
AA          BB
----------- -----------
11          1

(1 行受影响)

sql2000用临时表，加个自增列

[parss]

感谢各位热心的朋友们，现在结帐～～～～