如何将SQL语句中的两行结果合并到一行

[zhang_meixia]

有如这样的表：
name status
小张 普通员工
小张 组长
小二 经理
小三 老板
小三 员工

如何使查询出的结果为
小张 普通员工，组长
小二 经理
小三 老板，员工


还请各位帮忙

[feegle_develop]

IF OBJECT_ID('A') IS NOT NULL
  DROP TABLE A
GO

CREATE TABLE A
(
NAME VARCHAR(20),
STATU VARCHAR(50)
)
GO

INSERT INTO A
SELECT '小张','普通员工'
UNION ALL
SELECT '小张','组长'
UNION ALL
SELECT '小二','经理'
UNION ALL
SELECT '小三','老板'
UNION ALL
SELECT '小三','员工'
GO

SELECT DISTINCT NAME,RIGHT(STATUS,LEN(STATUS)-1)
FROM
(
SELECT *,
STATUS=(SELECT ','+LTRIM(STATU) FROM A WHERE NAME=T.NAME FOR XML PATH(''))
FROM A T
) A
GO

[喜-喜]

СÕÅСÈýС¶þ

[siegebaoniu]

看来要研究一下stuff，最近这个函数老出现！

[xierme_sun]

前几楼都回答正确，用stuff函数

[王向飞]

--> 数据库版本:
--> Microsoft SQL Server 2008 (RTM) - 10.0.1600.22
--> 测试数据：[TB]
IF  EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[TB]') 
AND type in (N'U')) 
DROP TABLE [TB]
GO

---->建表
create table [TB]([name] varchar(4),[status] varchar(8))
insert [TB]
select '小张','普通员工' union all
select '小张','组长' union all
select '小二','经理' union all
select '小三','老板' union all
select '小三','员工'
GO


SELECT a.name,
status =stuff((
select ','+convert(varchar(20),status) FROM [TB] WHERE name = a.name  for xml path(''))
,1,1,'')
FROM [TB] a 
group by a.name


--> 查询结果
SELECT * FROM [TB]
--> 删除表格
--DROP TABLE [TB]

[王向飞]

--> 数据库版本:
--> Microsoft SQL Server 2008 (RTM) - 10.0.1600.22
--> 测试数据：[TB]
IF  EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[TB]') 
AND type in (N'U')) 
DROP TABLE [TB]
GO

---->建表
create table [TB]([name] varchar(4),[status] varchar(8))
insert [TB]
select '小张','普通员工' union all
select '小张','组长' union all
select '小二','经理' union all
select '小三','老板' union all
select '小三','员工'
GO


SELECT a.name,
status =stuff((
select ','+convert(varchar(20),status) FROM [TB] WHERE name = a.name  for xml path(''))
,1,1,'')
FROM [TB] a 
group by a.name

SELECT   a.name,
status =STUFF(REPLACE(REPLACE(
(select status
FROM [TB]  
where name = a.name  
FOR XML AUTO
), '<TB status="', ','), '"/>', ''), 1, 1, '') 
FROM [TB] a 
group by a.name  
--> 查询结果
SELECT * FROM [TB]
--> 删除表格
--DROP TABLE [TB]

[Mr_Nice]

--> 测试数据：[TB]
if object_id('[TB]') is not null drop table [TB]
create table [TB]([name] varchar(4),[status] varchar(8))
insert [TB]
select '小张','普通员工' union all
select '小张','组长' union all
select '小二','经理' union all
select '小三','老板' union all
select '小三','员工'

select * from [TB]


select [name], [values]=stuff((select ','+[status] from tb t where [name]=tb.[name] for xml path('')), 1, 1, '') 
from tb 
group by [name] 

/*
name values
---- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
小二   经理
小三   老板,员工
小张   普通员工,组长

(3 行受影响)
*/


drop table tb 

[华夏小卒]

[王向飞]

[Quote=引用 4 楼 js_szy 的回复:]

[/Quote]

[sinpoal]

select b.name,
case when b.name='СÕÅ' then concat(b.status1,b.status2) end status ,
case when b.name='СÈý' then concat(b.status4,b.status5) end status,
case when b.name='С¶þ' then b.status3 end status
 from
(select t.name,
max(case when t.name='СÕÅ' and t.rn=1 then status else 'null' end) status1,
max(case when t.name='СÕÅ' and t.rn=2 then status else 'null' end) status2,
max(case when t.name='С¶þ' and t.rn=1 then status else 'null' end) status3,
max(case when t.name='СÈý' and t.rn=1 then status else 'null' end) status4,
max(case when t.name='СÈý' and t.rn=2 then status else 'null' end) status5
from
(select row_number() over(partition by name order by status) rn,t4.* 
 from t4) t group by name) b

[octwind]

if(object_id('person') is not null) drop table person
create table person(name varchar(10),status varchar(10))
insert into person
select '小张','普通员工' union all
select '小张', '组长' union all 
select '小二','经理' union all
select '小三','老板' union all
select '小三','员工'

if(object_id('GetPositionByName') is not null) drop function GetPositionByName
go
create function GetPositionByName(@name varchar(10))
returns varchar(10)
as
begin
declare @position varchar(10)
set @position = ''
select @position = @position + ',' + isnull(status,'')  from person where name = @name
select @position = stuff(@position,1,1,'')
return(@position)
end

select name,dbo.GetPositionByName(name) status from person group by name

[我的我的]

楼上的几位问一下，其中的 xml是sqlserver2008新赠的吗？
我用05 提示错误
Msg 170, Level 15, State 1, Line 3
第 3 行: 'xml' 附近有语法错误。

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