取连续的数据，要记录连续数据的开头和结尾

[rainfull]

现在有一组数据，是断断续续的数据，我现在有取连续的数据，要记录连续数据的开头和结尾

1
2
3
4
8
9
10
13
14
15
16
17

我要把这些连续的数据分段，第一段1-4，第二段8-10，第三段10-17

[rainfull]

给点思路，第一个好判断，到第二组数据怎么办

[jointan]

你凭什么把它们分为:
1-4,8-10，10-17

没看出规律来

[jsjhj2008]

int[] arry = new int[12] { 1, 2, 3, 4, 5, 8, 9, 23, 24, 25,1000,1001 };
        int flag = 1;
        for (int i = 0; i < arry.Length - 1; i++)
        {
            if (i == arry.Length - 2)
            {
                Response.Write("第" + flag.ToString() + "到" + arry[i + 1].ToString() + "</br>");
            }
            else if (arry[i] + 1 != arry[i + 1])
            {
                Response.Write("第" + flag.ToString() + "到" + arry[i].ToString() + "</br>");
                flag = arry[i + 1];
            }
        }

测试通过了，楼书试试

[rainfull]

int[] arry = new int[12] { 1, 3, 4, 5, 8, 9,13, 23, 24, 25,30,1000,1001 };

把是连续的剔除来

[rainfull]

int[] arry = new int[12] { 1, 3, 4, 5, 8, 9,13, 23, 24, 25,30,1000,1001 };

把不是连续的剔除来

[jsjhj2008]

不对吗？详细点说说呢，举个例子

[kensouterry]

一个控制台，不连续的懒得写了

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Data.SqlClient;
using System.Data;

namespace Temp
{
    class Program
    {
        int[] array = new int[13] { 1, 3, 4, 5, 8, 9, 13, 23, 24, 25, 30, 1000, 1001 };
        
        List<int> begin = new List<int>();
        List<int> end = new List<int>();

        //The method only satisfy increased sequence number.
        public void GetContinuousSequence(int[] array)
        {
            int k = 0;
            int times = 0;
            for (int i = 0; i < array.Length; i++)
            {
                //Judging the last sequence.
                if (i == array.Length - 1)
                {
                    begin.Add(k + 1 - times);
                    end.Add(k + 1);
                    break;
                }
                //the number will be set as a sub-continuous-sequence number's beginning.
                if (array[i] == array[i + 1] - 1)
                {
                    k = array[i];
                    times++;
                }
                if ((array[i] != array[i + 1] - 1)&& times!=0)
                {
                    begin.Add(k + 1 - times);
                    end.Add(k + 1);
                    times = 0;
                }
            }
            //Now,you can get serveral pairs exist in List begin and List end,which records continuous sequence's beginning number and end number at the same index.
            List<int> sequenceList = ExtendSequenceNumber(begin, end);

            //Display sequence number.
            for (int i = 0; i < sequenceList.Count; i++)
            {
                Console.WriteLine("{0},", sequenceList[i]);
            }
        }

        private List<int> ExtendSequenceNumber(List<int> begin, List<int> end)
        {
            List<int> listSequence = new List<int>();
            for (int i = 0; i < begin.Count; i++)
            {
                for (int j = begin[i]; j < end[i]+1; j++)
                {
                    listSequence.Add(j);
                }
            }
            return listSequence;
        }

        static void Main(string[] args)
        {
            Program p1 = new Program();
            p1.GetContinuousSequence(p1.array);

            Console.WriteLine("finish...");
            Console.ReadLine();
        }

    }
}

[spx427]

public int[] data= {1,2,3,4,8,9,10,13,14,15,16,17};
public List<int> start = new List<int>();
public List<int> end = new List<int>();

public void method()
{
start.Add(data[0]);
for (int i = 0; i < data.Length - 1;i++ )
{

if (data[i + 1] - data[i] != 1)
{
end.Add(data[i]);
start.Add(data[i + 1]);
}
if (i == data.Length - 2)
{
end.Add(data[i+1]);
}
}

}

开头和结尾分别记在start和end两个集合里面了。

[gongsun]

[Quote=引用 2 楼 jointan 的回复:]
你凭什么把它们分为:
1-4,8-10，10-17

没看出规律来
[/Quote]

应该是 1-4,8-10，13-17

lz写错了。

按照 递增+1

先 int m[] 装你所有的数

在 循环 去判断...(m[i=1] - m[i] 是否=1 )

再搞一个2维数组装 就可以了

a[0][0]=1
a[0][1]=2
a[0][2]=3
a[0][3]=4

a[1][0]=8
a[1][1]=9
a[1][2]=10

...

[rainfull]

[Quote=引用 3 楼 spx427 的回复:]
public int[] data= {1,2,3,4,8,9,10,13,14,15,16,17};
public List<int> start = new List<int>();
public List<int> end = new List<int>();

public void method()
{
start.Add(data[0]);
for……
[/Quote]

现在再问一个问题，如果我把这个数组改一下，1,3,4,5,6,9,10,11,12,16,17,18,19,25
我怎么将他们断开列！

[rainfull]

现在再问一个问题，如果我把这个数组改一下，1,3,4,5,6,9,10,11,12,14,16,17,18,19,25
我怎么将他们断开列！

[rainfull]

要剔除不是连续的