MYSQL语句错误

meceky 2010-09-09 02:56:11
MySQL数据库中

update games set games.status = 2 inner join gameapplyways
on games.id = gameapplyways.game_id
where gameapplyways.apply_deadline < curdate()
and games.status = 7 and games.id = 6

这句SQL老是提示错误。为什么啊?
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'inner join gameapplyways
on games.id = gameapplyways.game_id
where gameapplyw' at line 1
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ciray 2010-09-09
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跨表更新是需要先连接的,inner join 要写在set之前才行。
meceky 2010-09-09
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[Quote=引用 3 楼 meceky 的回复:]

引用 1 楼 jakey9826 的回复:

SQL code
update games, gameapplyways set games.status = 2 where gameapplyways.apply_deadline < curdate() and games.status = 7 and games.id = 6 and games.id = gameapplyways.……
[/Quote]
test
meceky 2010-09-09
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[Quote=引用 1 楼 jakey9826 的回复:]

SQL code
update games, gameapplyways set games.status = 2 where gameapplyways.apply_deadline < curdate() and games.status = 7 and games.id = 6 and games.id = gameapplyways.game_id


注意upd……
[/Quote]
引用
meceky 2010-09-09
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[Quote=引用 1 楼 jakey9826 的回复:]

SQL code
update games, gameapplyways set games.status = 2 where gameapplyways.apply_deadline < curdate() and games.status = 7 and games.id = 6 and games.id = gameapplyways.game_id


注意upd……
[/Quote]
以前一直用Mssql,谢谢!!
程序猿之殇 2010-09-09
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update games, gameapplyways set games.status = 2 where gameapplyways.apply_deadline < curdate()  and games.status = 7 and games.id = 6 and games.id = gameapplyways.game_id 


注意update与select的区别。

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