疯了，有没有一句简单的话搞定

[phyedu]

越弄越复杂，结果问题还没有解决，
有如下数据
ID XH
A 1
A 2
A 3
B 4
B 5
C 6
C 7
D 8
得到如下排列
ID XH
A 1
B 4
C 6
D 8
A 2
B 5
C 7
A 3

[liangCK]

SELECT * FROM tb
ORDER BY ROW_NUMBER() OVER(PARTITION BY ID ORDER BY XH);


SELECT * FROM tb AS A
ORDER BY (SELECT COUNT(*) FROM tb 
           WHERE ID=A.ID AND XH < A.XH)

[dawugui]

--sql 2000

select id , xh from
(
select t.* , px = (select count(1) from tb where id = t.id and xh < t.xh) + 1 from tb t
) m
order by px , id

[dawugui]

-- sql 2005
select id , xh from
(
select t.* , px = row_number() over(partition by id order by xh) from tb t
) m
order by px , id

[dawugui]

create table tb(ID varchar(10),XH int)
insert into tb values('A', 1)
insert into tb values('A', 2)
insert into tb values('A', 3)
insert into tb values('B', 4)
insert into tb values('B', 5)
insert into tb values('C', 6)
insert into tb values('C', 7)
insert into tb values('D', 8)
go

--sql 2000

select id , xh from
(
select t.* , px = (select count(1) from tb where id = t.id and xh < t.xh) + 1 from tb t
) m
order by px , id

drop table tb

/*

id         xh          
---------- ----------- 
A          1
B          4
C          6
D          8
A          2
B          5
C          7
A          3

（所影响的行数为 8 行）

*/

create table tb(ID varchar(10),XH int)
insert into tb values('A', 1)
insert into tb values('A', 2)
insert into tb values('A', 3)
insert into tb values('B', 4)
insert into tb values('B', 5)
insert into tb values('C', 6)
insert into tb values('C', 7)
insert into tb values('D', 8)
go

-- sql 2005
select id , xh from
(
select t.* , px = row_number() over(partition by id order by xh) from tb t
) m
order by px , id

drop table tb

/*

id         xh
---------- -----------
A          1
B          4
C          6
D          8
A          2
B          5
C          7
A          3

(8 行受影响)


*/

[貓哥是個傳說]

學習一下