正则表达式求助

[niesen111]

href=\"http://t.sina.com.cn/1257866011/wr0nXUadCl\"><STRONG lang=CL1005>原文转发</STRONG><STRONG type=\"rttCount\" rid=\"201100921262435629\">(250)</STRONG></A><SPAN class=MIB_line_l>|</SPAN><A href=\"http://t.sina.com.cn/1257866011/wr0nXUadCl\"><STRONG lang=CC0603>原文评论</STRONG><STRONG type=\"commtCount\" rid=\"201100921262435629\">(287)</STRONG></A></SPAN></P>\r\n<DIV
求救：原文转发的数字250，原文评论的数字287如何匹配？

[bingshanzhiling]

这其中只有两个()组，直接匹配这两个就可以了啊

[-过客-]

try...

Regex reg = new Regex(@"(?s)原文转发(?:<[^>]*>)*\((\d+)\).*?原文评论(?:<[^>]*>)*\((\d+)\)");
MatchCollection mc = reg.Matches(yourStr);
foreach (Match m in mc)
{
    richTextBox2.Text += m.Groups[1].Value + "\n";
    richTextBox2.Text += m.Groups[2].Value + "\n";
}

[niesen111]

如何写成捕获的形式呢？

[-过客-]

这已经是捕获组了，非要写成命名捕获组？

Regex reg = new Regex(@"(?s)原文转发(?:<[^>]*>)*\((?<transmit>\d+)\).*?原文评论(?:<[^>]*>)*\((?<comment>\d+)\)");
MatchCollection mc = reg.Matches(yourStr);
foreach (Match m in mc)
{
    richTextBox2.Text += m.Groups["transmit"].Value + "\n";
    richTextBox2.Text += m.Groups["comment"].Value + "\n";
}