字符串遍历处理

[jy02418676]

如 string i='12,13,14,234,23'

我需要做成 '12','13','14','234','23’

有什么好办法么，我想到的办法太麻烦了，效率太低

[threenewbee]

Split函数。

[wuyq11]

List<string> list = new List<string> { "1", "2", "3" };
string result = string.Join(",", list.ConvertAll(delegate(string s) { return string.Format("'{0}'", s); }).ToArray());

string str="";
str = String.Join("','",str.Split(new char[]{','},StringSplitOptions.RemoveEmptyEntries));
str = "'" + str + "'";

[lqkankan]

没明白 啥意思

string i ="12,13,14,234,23";
string[] tem = i.split(',');
for(int j=0;i<tem.length;j++)
 //do what you want

string a = "'12','13','14','234','23’";//这样？
//还是
string b = "12','13','14','234','23"; //这样？

[liuh6]

string []iList_=i.Split(',');

数据里的就是你要的东西..

[hongjiaoli]

string i ="12,13,14,234,23";
string[] tem = i.split(',');

[铛铛]

string i='12,13,14,234,23'

这是什么东西，字符吗？这么长？

如果是string i=“12,13,14,234,23”;
string[] strs = i.Split(',');

[Wilson_Zhong]

string i='12,13,14,234,23';
string[] iStr=i.split(',');

iStr[i]即为'12','13','14','234','23’

[kensouterry]

呵呵，帮你整合一下。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Collections;

namespace ConsoleApplication1
{
    class Program
    {
        string[] arraySplit;

        public Program()
        {
            string i = "12,13,14,234,23";

            arraySplit = i.Split(new string[1] { "," }, StringSplitOptions.RemoveEmptyEntries);
            //arraySplit变量里面就存放了你需要的字符串
            //Display the split string in Console.
            for (int j = 0; j < arraySplit.Length; j++)
            {
                Console.WriteLine("{0}:{1}", j, arraySplit[j]);
            }
        }

        static void Main()
        {
            Program p1 = new Program();

            Console.ReadLine();
        }
    }

}