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分享基于oracle的Hibernate例子出现问题，百分求解
我刚刚开始学习Hibiscus，运行的时候出现如下问题，哪位大侠能帮忙解决，百分感谢
Exception in thread "main" org.hibernate.MappingException: Could not determine type for: java.lang.Sting, at table: guestbook, for columns: [org.hibernate.mapping.Column(name)]
Exception in thread "main" org.hibernate.MappingException: Could not determine type for: java.lang.Sting, at table: guestbook, for columns: [org.hibernate.mapping.Column(name)]
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lisai17 2010-10-03
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非常感谢，我居然这个没看出来.........
lsq1988512 2010-10-03
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[Quote=引用 2 楼 magong 的回复:]
<class name="User" table="guestbook" lazy="true">
<property name="name" column="USER_NAME" type="java.lang.String" />
</class>
[/Quote]
真是好眼力 String 写成Sting
<class name="User" table="guestbook" lazy="true">
<property name="name" column="USER_NAME" type="java.lang.String" />
</class>
[/Quote]
真是好眼力 String 写成Sting
sun0322 2010-10-03
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Exception in thread "main" org.hibernate.MappingException: Could not determine type for: java.lang.Sting, at table: guestbook, for columns: [org.hibernate.mapping.Column(name)]
sun0322 2010-10-03
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[Quote=引用 2 楼 magong 的回复:]
<class name="User" table="guestbook" lazy="true">
<property name="name" column="USER_NAME" type="java.lang.String" />
</class>
[/Quote]
好眼力
<class name="User" table="guestbook" lazy="true">
<property name="name" column="USER_NAME" type="java.lang.String" />
</class>
[/Quote]
好眼力
magong 2010-10-03
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<class name="User" table="guestbook" lazy="true">
<property name="name" column="USER_NAME" type="java.lang.String" />
</class>
<property name="name" column="USER_NAME" type="java.lang.String" />
</class>
lisai17 2010-10-03
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期待各位大侠的答案！
