查询数据库 中第31-40条记录，id自增长不是连续，SQL如何实现？

with cte as(

select row_number() over(order by UserID asc) as row_number,* from Users

)

select * from cte where row_number between 31 and 40

--2000



select * from 

   (select * ,id1=(select count(1)+1 from tb a where a.id<tb.id)   from tb) t

    where id1 between n and m

1.    

select top m * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/)    

  

2.    

select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表    

set rowcount n   --只取n条结果   

select * from 表变量 order by columnname desc    

  

3.    

select top n * from     

(select top m * from tablename order by columnname) a    

order by columnname desc    

  

  

4.如果tablename里没有其他identity列，那么：    

先生成一个序列,存储在一临时表中.   

select identity(int) id0,* into #temp from tablename    

  

取n到m条的语句为：    

select * from #temp where id0 > =n and id0  <= m    

  

如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行：    

exec sp_dboption 你的DB名字,'select into/bulkcopy',true    

  

  

5.如果表里有identity属性，那么简单：    

select * from tablename where identity_col between n and m     

  

6.SQL2005开始.可以使用row_number() over()生成行号   

;with cte as  

(   

 select id0=row_number() over(order by id),* from tablename   

)   

select * from cte where id0 between n to m



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row_number()