查询数据库 中第31-40条记录,id自增长不是连续,SQL如何实现?

程序一员 2010-10-27 08:55:28
查询数据库一张表 中第31-40条记录,id自增长不是连续,SQL如何实现?
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程序一员 2010-10-27

with cte as(
select row_number() over(order by UserID asc) as row_number,* from Users
)
select * from cte where row_number between 31 and 40
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catherinelzl 2010-10-27
还可以这样

SELECT * FROM
(
SELECT A.*, ROWNUM RN
FROM (SELECT * FROM tb) A
)
WHERE RN >= 31 and rn<=40
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kevin87923 2010-10-27

select top 10 * from A where id not in (select top 30 id from A)
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catherinelzl 2010-10-27
oracle的写法:
SELECT * FROM
(
SELECT A.*, ROWNUM RN
FROM (SELECT * FROM tb) A
WHERE ROWNUM <= 40
)
WHERE RN >= 31
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abuying 2010-10-27
--2000

select * from
(select * ,id1=(select count(1)+1 from tb a where a.id<tb.id) from tb) t
where id1 between n and m

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Mr_Nice 2010-10-27
[Quote=引用 1 楼 orchidcat 的回复:]

SQL code
row_number()
[/Quote]
参考!http://technet.microsoft.com/zh-cn/library/ms186734(SQL.90).aspx
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zsh0809 2010-10-27
1.    
select top m * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/)

2.
select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表
set rowcount n --只取n条结果
select * from 表变量 order by columnname desc

3.
select top n * from
(select top m * from tablename order by columnname) a
order by columnname desc


4.如果tablename里没有其他identity列,那么:
先生成一个序列,存储在一临时表中.
select identity(int) id0,* into #temp from tablename

取n到m条的语句为:
select * from #temp where id0 > =n and id0 <= m

如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行:
exec sp_dboption 你的DB名字,'select into/bulkcopy',true


5.如果表里有identity属性,那么简单:
select * from tablename where identity_col between n and m

6.SQL2005开始.可以使用row_number() over()生成行号
;with cte as
(
select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m

本文来自CSDN博客,转载请标明出处:http://blog.csdn.net/ws_hgo/archive/2009/02/18/3906309.aspx
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Mr_Nice 2010-10-27
row_number() 


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