行转列问题

[GritH2O]

表1 t1
id name age
1 aa 22
2 bb 33
3 cc 30
4 dd 31

表2 t2
id adate meno
1 2002-1-1 s1
2 2002-1-1 s3
1 2002-1-1 s7
3 2003-1-1 s4
1 2003-1-1 s2
2 2004-1-1 s5
3 2004-1-1 s6

结果
id name age 2002-1-1 2002-1-1 2003-1-1 2004-1-1
1 aa 22 s1 s7 s2
2 bb 33 s3 s5
3 cc 30 s4 s6
4 dd 31

结果的列是根据表2的数据自动生成的 如果表2添加数据则结果中列增加
注意结果中的列有重复的
想要得到这个结果集，不知道弄

[GritH2O]

结果
id name age 2002-1-1 2002-1-1 2003-1-1 2004-1-1
1 aa 22 s1 s7 s2
2 bb 33 s3 s5
3 cc 30 s4 s6
4 dd 31

[dawugui]

你这个行列转换，数据恐怕有问题吧。
建议改为：
id name age date1 date2 date3 date4
1 aa 22 s1 s7 s2
2 bb 33 s3 s5
3 cc 30 s4 s6
4 dd 31

[GritH2O]

<table width="381" border="1">
  <tr>
    <td width="14">id</td>
    <td width="28">name</td>
    <td width="21">age</td>
    <td width="69">2002-1-1</td>
    <td width="65">2002-1-1</td>
    <td width="67">2003-1-1</td>
    <td width="71">2004-1-1</td>
  </tr>
  <tr>
    <td>1</td>
    <td>aa</td>
    <td>22</td>
    <td>s1</td>
    <td>s7</td>
    <td>s2</td>
    <td> </td>
  </tr>
  <tr>
    <td>2</td>
    <td>bb</td>
    <td>33</td>
    <td>s3</td>
    <td> </td>
    <td> </td>
    <td>s5</td>
  </tr>
  <tr>
    <td>3</td>
    <td>cc</td>
    <td>30</td>
    <td> </td>
    <td> </td>
    <td>s4</td>
    <td>s6</td>
  </tr>
  <tr>
    <td>4</td>
    <td>dd</td>
    <td>31</td>
    <td> </td>
    <td> </td>
    <td> </td>
    <td> </td>
  </tr>
</table>

[dawugui]

--sql 2000静态
select t1.* ,
       max(case px when 1 then meno else '' end) date1,
       max(case px when 2 then meno else '' end) date2,
       max(case px when 3 then meno else '' end) date3
from t1 , 
(select t.* , px = (select count(1) from t2 where id = t.id and adate < t.adate) = 1 from t2 t) m
where t1.id = m.id
group by t1.id , t1.name , t1.meno

--sql 2000动态
declare @sql varchar(8000)
set @sql = 'select t1.* '
select @sql = @sql + ' , max(case px when ''' + cast(px as varchar) + ''' then meno else '''' end) [date' + cast(px as varchar) + ']'
from (select distinct px from (select t.* , px = (select count(1) from t2 where id = t.id and adate < t.adate) = 1 from t2 t) m ) as a
set @sql = @sql + ' from t1 , 
(select t.* , px = (select count(1) from t2 where id = t.id and adate < t.adate) = 1 from t2 t) m
where t1.id = m.id
group by t1.id , t1.name , t1.meno'
exec(@sql) 

[GritH2O]

结果
id name age 2002-1-1 2002-1-1 2003-1-1 2004-1-1
1 aa 22 s1 s7 s2
2 bb 33 s3 s5
3 cc 30 s4 s6
4 dd 31

[GritH2O]

我考 结果怎么就发不上来呢？
位置总是不对

[GritH2O]

请问你 你的那个px是什么？

[abuying]

[Quote=引用 7 楼 grith2o 的回复:]

请问你 你的那个px是什么？
[/Quote]
就是新的结果集的重新编号，类似于idenity(int ,1,1)