ruby将16进制转10进制问题

[wuyuanzhe]

有一串16进制字符串，如“01 01 01 01”、“a1 01 b1 01”等

需要将其转成十进制，如“01 01 01 01”---> “1010101” ----> 16843009
“a1 01 b1 01”---> “a101b101” ----> 2701242625

如何操作?
请教各位达人～～～

[helstorm]

a = '01 01 01 01' #---> “1010101” ----> 16843009

a.gsub!(/\s/, '')
ia = a.to_i(16)
p ia

b = 'a1 01 b1 01' #---> “a101b101” ----> 2701242625

b.gsub!(/\s/, '')
ib = b.to_i(16)
p ib

[wuyuanzhe]

这个没见有转到10进制的操作啊？
本来就是16进制的，转到最后还是16进制的，基本没用啊

[helstorm]

唉，你至少运行一下再来回帖吧。

/*
 *  call-seq:
 *     str.to_i(base=10)   -> integer
 *
 *  Returns the result of interpreting leading characters in <i>str</i> as an
 *  integer base <i>base</i> (between 2 and 36). Extraneous characters past the
 *  end of a valid number are ignored. If there is not a valid number at the
 *  start of <i>str</i>, <code>0</code> is returned. This method never raises an
 *  exception when <i>base</i> is valid.
 *
 *     "12345".to_i             #=> 12345
 *     "99 red balloons".to_i   #=> 99
 *     "0a".to_i                #=> 0
 *     "0a".to_i(16)            #=> 10
 *     "hello".to_i             #=> 0
 *     "1100101".to_i(2)        #=> 101
 *     "1100101".to_i(8)        #=> 294977
 *     "1100101".to_i(10)       #=> 1100101
 *     "1100101".to_i(16)       #=> 17826049
 */

[helstorm]

/*
* call-seq:
* str.to_i(base=10) -> integer
*
* Returns the result of interpreting leading characters in <i>str</i> as an
* integer base <i>base</i> (between 2 and 36). Extraneous characters past the
* end of a valid number are ignored. If there is not a valid number at the
* start of <i>str</i>, <code>0</code> is returned. This method never raises an
* exception when <i>base</i> is valid.
*
* "12345".to_i #=> 12345
* "99 red balloons".to_i #=> 99
* "0a".to_i #=> 0
* "0a".to_i(16) #=> 10
* "hello".to_i #=> 0
* "1100101".to_i(2) #=> 101
* "1100101".to_i(8) #=> 294977
* "1100101".to_i(10) #=> 1100101
* "1100101".to_i(16) #=> 17826049
*/

[wuyuanzhe]

看错了
to_i看成to_s了。。。
sorry