一个简单的数组问题，急救！！！！

[woshimajia0005]

数组1：
一个一维数组 用户姓名
$name = {'wangkang', 'tangchen', 'zhanghua'}

数组2:
一个二维数组 用户姓名 用户年龄
age = {
[0] = array(
[username] = 'chenwen',
[userage] = 39
)
[1] = array(
[username] = 'tangchen',
[userage] = 31
)
[2] = array(
[username] = 'kangkang',
[userage] = 33
)
[3] = array(
[username] = 'wangkang',
[userage] = 33
)
}

返回 数组1中的那些用户 而且 数组2中有年龄。

例如 上面的返回：
age = {
[0] = array(
[username] = 'wangkang',
[userage] = 33
)
[1] = array(
[username] = 'tangchen',
[userage] = 31
)
}

[沪php攻城师]

$name = array('wangkang', 'tangchen', 'zhanghua');
$age = array(
  0 => array(
  "username" => 'chenwen',
  "userage" => 39
  ),
  1 => array(
  "username" => 'tangchen',
  "userage" => 31
  ),
  2 => array(
  "username" => 'kangkang',
  "userage" => 33
  ),
  3 => array(
  "username" => 'wangkang',
  "userage" => 33
  )
);
$arr = array();
foreach ($age as $v)
{
	if(in_array($v['username'],$name))
	{
		$arr[] = $v;
	}
}
echo "<pre>";
print_r($arr);
echo "</pre>";

结果：

Array
(
    [0] => Array
        (
            [username] => tangchen
            [userage] => 31
        )

    [1] => Array
        (
            [username] => wangkang
            [userage] => 33
        )

)

[woshimajia0005]

[Quote=引用 1 楼 jzh2004 的回复:]

PHP code

$name = array('wangkang', 'tangchen', 'zhanghua');
$age = array(
0 => array(
"username" => 'chenwen',
"userage" => 39
),
1 => array(
"username" => 'tangchen',
"userage" => 31……
[/Quote]

谢谢 你这方法是可以

我是 想知道有没有更简单 更快速的

[在-云端]

[Quote=引用 1 楼 jzh2004 的回复:]

PHP code

$name = array('wangkang', 'tangchen', 'zhanghua');
$age = array(
0 => array(
"username" => 'chenwen',
"userage" => 39
),
1 => array(
"username" => 'tangchen',
"userage" => 31……
[/Quote]

楼上正解!