关于ArrarList的输出，不太明白，求助~

[dabanphoto]

import java.util.ArrayList;


public class TestPerson2{

	/**
	 * @param args
	 */
	public static void main(String[] args) {
		
		//Person2[] p = new Person2[5];
		//p[0]= new Person2("li", 44, 2300);
		//p[1]= new Person2("zhang", 44, 2300);
		//p[2]= new Person2("wang", 44, 2300);
		//p[3]= new Person2("zhao", 44, 2300);
		//p[4]= new Person2("ma", 44, 2300);
	
		//for (int i=0; i<p.length; i++){
		//	System.out.println("name:" + p[i].name + " age:" + p[i].age + " salary:" + p[i].salary );
		//}
		
		ArrayList<Person2> a = new ArrayList<Person2>();
		
		a.add(new Person2("Li", 44, 2300));
		a.add(new Person2("Zhang", 40, 3000));
		
		for(int i =0 ; i<a.size() ; i++){
			System.out.println(......);
		}
		
		
	}

}

class Person2{
	
	String name;
	int age;
	double salary;
	
	Person2(String name, int age, double salary){
		this.name = name;
		this.age = age;
		this.salary = salary;
	}
	
	public String getName(){
		return name;
	}
}

System.out.println(......);这里该怎么输出呢，就象我注释掉的普通数组那样按行分别输出name,age和salary。

[WCliverpool]

System.out.println("name:"+a[i].name+"age:"+a[i].age+" salary:" + a[i].salary )

ArrayList 动态数组本质上还是一个数组啊，所以跟你之前的是很类似的

[houjin_cn]

实现一个toString方法就可以直接输出了;

import java.util.ArrayList;

public class TestPerson2{

	/**
	 * @param args
	 */
	public static void main(String[] args) {
        ArrayList<Person2> a = new ArrayList<Person2>();
        
        a.add(new Person2("Li", 44, 2300));
        a.add(new Person2("Zhang", 40, 3000));
        
        for(int i =0 ; i<a.size() ; i++){
            System.out.println(a.get(i));
        }
    }
}

class Person2{

	String name;
	int age;
	double salary;

	Person2(String name,int age,double salary){
		this.name=name;
		this.age=age;
		this.salary=salary;
	}

	public String getName(){
		return name;
	}
	
	public String toString(){
		return "name:" + name + " age:" + age + " salary:" + salary;
	}
}

[zms67598]

如果你不想用toString()的话，你也可以这样
import java.util.ArrayList;
import java.util.List;


public class TestPerson2{
public static void main(String[] args) {
List<Person2> a = new ArrayList<Person2>();
Person2 person = null;
a.add(new Person2("Li", 44, 2300));
a.add(new Person2("Zhang", 40, 3000));

for(int i =0 ; i<a.size() ; i++){
person = a.get(i);
System.out.println("name: "+
person.name+" "+"age: "+
person.age+" "+"salary: "+
person.salary);
}


}

}

class Person2{

String name;
int age;
double salary;

Person2(String name, int age, double salary){
this.name = name;
this.age = age;
this.salary = salary;
}

public String getName(){
return name;
}
}

[taiyangzilei]

import java.util.ArrayList;

public class TestPerson2{

/**
* @param args
*/
public static void main(String[] args) {
ArrayList<Person2> a = new ArrayList<Person2>();

a.add(new Person2("Li", 44, 2300));
a.add(new Person2("Zhang", 40, 3000));

foreach(Person2 p in a){
System.out.println(p);
}
}
}

class Person2{

String name;
int age;
double salary;

Person2(String name,int age,double salary){
this.name=name;
this.age=age;
this.salary=salary;
}

public String getName(){
return name;
}

public String toString(){
return "name:" + name + " age:" + age + " salary:" + salary;
}
}

集合的遍历一般用foreach()

[dabanphoto]

谢谢大家啦。。。。