PHP中如何把excel导入并替换数据库表中的内容

[qwe_121]

$db = create_peardb_handle();
$subHotel_temp=fopen("test.csv","r");//连接EXCEL文件,格式为了.csv
$subHotel_q=$db->query("insert into hotel_activities_2(hotel_id,start_date,end_date,content,s_type) values('");
while ($subHotel_data = fgetcsv ($subHotel_temp, 1000, ",")) {
   $subHotel_num = count ($subHotel_data);
for ($i=0;$i<$subHotel_num;$i++) 
{
       if($i==$subHotel_num-1){$subHotel_q=$subHotel_q.$subHotel_data[$i]."')";break;}
       $subHotel_q=$subHotel_q.$subHotel_data[$i]."','";
   }
   echo "SQL语句执行成功";
$sql=$db->query("insert into hotel_activities_2(hotel_id,start_date,end_date,content,s_type) values('");
fclose ($subHotel_temp);

报错：
Warning: fopen(test.csv) [function.fopen]: failed to open stream: No such file or directory in /var/www/2009/webroot/subject/hotel_admin/subHotel_import.php on line 7

Warning: fgetcsv() expects parameter 1 to be resource, boolean given in /var/www/2009/webroot/subject/hotel_admin/subHotel_import.php on line 9

[amani11]

No such file or directory

说明没这个文件存在。。。。检测CSV目录所在

[在-云端]

报错：
Warning: fopen(test.csv) [function.fopen]: failed to open stream: No such file or directory in /var/www/2009/webroot/subject/hotel_admin/subHotel_import.php on line 7

Warning: fgetcsv() expects parameter 1 to be resource, boolean given in /var/www/2009/webroot/subject/hotel_admin/subHotel_import.php on line 9


1.你给的文件没找到

2.fgetcsv需要的参数类型不对

[qwe_121]

[Quote=引用 2 楼 heyc1998 的回复:]

报错：
Warning: fopen(test.csv) [function.fopen]: failed to open stream: No such file or directory in /var/www/2009/webroot/subject/hotel_admin/subHotel_import.php on line 7

Warning: fgetcsv() expec……
[/Quote]

我没做过这个，到底怎么改啊，大侠救命啊。。。。。。。。。。。。。。