.net中如何取出xml中最后10条信息(也就是最新信息)

[zwj000]

.net中如何取出xml中最后10条信息(也就是最新信息)

[q107770540]

把你的XML帖出来看看

[zwj000]

<news>
<new id="1">
<title>Test</title>
<content>asdfsadfsadgsdagsdg</content>
<time>2010-11-18 15:40:25</time>
</new>
<new id="2">
<title>hhhhhh</title>
<content>jjjjjjjjj</content>
<time>2010-11-18 15:42:17</time>
</new>
<new id="3">
<title>qqqqqq</title>
<content>sssssssss</content>
<time>2010-11-18 15:42:49</time>
</new>
<new id="4">
<title>sssssssss</title>
<content>ddddddddddd</content>
<time>2010-11-18 15:46:30</time>
</new>
<new id="5">
<title>nihaoya</title>
<content>ffffffff</content>
<time>2010-11-18 15:50:37</time>
</new>
<new id="6">
<title>nihaoya</title>
<content>ffffffff</content>
<time>2010-11-18 15:50:37</time>
</new>
<new id="7">
<title>nihaoya</title>
<content>ffffffff</content>
<time>2010-11-18 15:50:37</time>
</new>
<new id="8">
<title>nihaoya</title>
<content>ffffffff</content>
<time>2010-11-18 15:50:37</time>
</new>
<new id="9">
<title>nihaoya</title>
<content>ffffffff</content>
<time>2010-11-18 15:50:37</time>
</new>
<new id="10">
<title>nihaoya</title>
<content>ffffffff</content>
<time>2010-11-18 15:50:37</time>
</new>
<new id="11">
<title>nihaoya</title>
<content>ffffffff</content>
<time>2010-11-18 15:50:37</time>
</new>
</news>

[newdigitime]

xml
首先用lastchild取最后一条,即最新条
然后用当前节点的previousSibling取上一样,依次类推,直至满10条

或者用childNodes集合
再用 for (var i=集合.length-1;i=0;i--)

[g_lbz]

LinqToXml如下，先按照时间进行排序，然后去前10个

            XDocument xDoc = XDocument.Load("D:\\aa.xml");

            var mySet = xDoc.Elements("new").OrderByDescending(x => DateTime.Parse(x.Element("time").Value))
                .Take(10)
                .Select(x => new {
                    title = x.Element("title").Value,
                    content = x.Element("content").Value,
                    time = x.Element("time").Value
                }).ToList();

[g_lbz]

上面的有点小bug，正确的如下

            var mySet = xDoc.Element("news").Elements("new").OrderByDescending(x => DateTime.Parse(x.Element("time").Value))
                .Take(10)
                .Select(x => new {
                    title = x.Element("title").Value,
                    content = x.Element("content").Value,
                    time = x.Element("time").Value
                }).ToList();

[zwj000]

[Quote=引用 5 楼 g_lbz 的回复:]
上面的有点小bug，正确的如下

C# code

var mySet = xDoc.Element("news").Elements("new").OrderByDescending(x => DateTime.Parse(x.Element("time").Value))
.Take(10)
.……
[/Quote]
不用linq，用document这种方式遍历，怎么弄？

[Abcsj]

 XmlDocument XmlDoc = new XmlDocument();

            XmlNodeList list = XmlDoc.GetElementsByTagName("new");
  for (int i = list.Count; i > list.Count-10; i++)
        {
         }