getJSON 不执行回调函数的问题

[zyang198811]

js:
function check(domain)
{
var otitle = null;
var title = null;

otitle = $("#txtchatquestion");
title = otitle.val();
title=title.replace(/[ ]/g,"");
if(title=="")
{
alert('请输入问题内容！');
return ;
}
var url =
"http://ashx."+domain+"/ChatAjax.ashx?time=" + Math.random() + "&callback=?";
$.getJSON(
url,
{"type":"tijiao","tijiao_content":""+title+""},
function(json){
alert(json.msg);
}
);
}

ashx:
string callback = context.Request.QueryString["callback"];

content = context.Request.QueryString["tijiao_content"].ToString();
string sql = string.Empty;
DBOracle ora = new DBOracle();
sql = "insert into web_question(title,content) values('" + content + "','" + content + "')";
int num = ora.ExecSql(sql);
context.Response.ContentType = "text/plain";
if (num > 0)
{
context.Response.Write(callback + "({\"msg\":\"添加成功！\"})");
}
else
{
context.Response.Write(callback + "({\"msg\":\"添加失败！\"})");
}
context.Response.End();

如上代码 总是不执行回调函数 各位大侠 帮忙看看 js报错 缺少' ; ' 分号


补充一下：能将数据传入ashx 并成功插入数据库 就是不能将数据返回js页面 我用getJSON 是因为要跨域！

[孟子E章]

context.Response.ContentType = "application/json";
试试

[zyang198811]

net_lover 好强大 非常谢谢 ok了 结贴！

[suc_qq]

servlet 呢

[gaubee]

看看答案