急求一个SQL视图

[jiangbo1125]

我有一张表A
a b
1 ,2,
2 ,2,3,

我想做个视图

a b
1 2
2 2
2 3


可以实现吗？

[ws_hgo]

if object_id('[TB]') is not null drop table [TB]    
 go    
 create table [TB]([COL1] varchar(3),[COL2] varchar(18))     
  insert [TB]     
  select 'ABC','123,4568,1234565' union all     
  select 'DBD','1231,56455,5645665'     
  GO     
     
 select B.[COL1],substring(B.[COL2],p.number,charindex(',',B.[COL2]+',',p.number)-p.number) [COL2]    
 from TB B    
 join master..spt_values p    
 on p.type='P'    
 and charindex(',',','+B.[COL2],number)=number     
     
COL1 COL2   
---- ------------------   
ABC  123   
ABC  4568   
ABC  1234565   
DBD  1231   
DBD  56455   
DBD  5645665   
(6 行受影响)  

本文来自CSDN博客，转载请标明出处：http://blog.csdn.net/ws_hgo/archive/2010/09/28/5912364.aspx

[华夏小卒]

create view vv
as

select a,
b=substring(right(b,len(b)-1),charindex(right(b,len(b)-1),',',number)-number)
from a t,master..spt_values s
where type='p' and number>0
and substring(left(b,len(b)-1),len(b)-1),,number,1)=','

try

[飘零一叶]

CREATE TABLE A
(
  A INT,
  B VARCHAR(10) 
)
INSERT INTO A
SELECT 1,',2,' UNION ALL
SELECT 2,',2,3,'

CREATE VIEW VIEW_A
AS
SELECT A.A, B.value FROM
(
  SELECT A, B = CONVERT(xml,'<root><v>' + REPLACE(B, ',', '</v><v>') + '</v></root>') FROM A
) A OUTER APPLY
(
  SELECT value = N.v.value('.', 'varchar(100)') FROM A.B.nodes('/root/v') N(v)
) B
WHERE B.value<>''

SELECT * FROM VIEW_A
---------
A	value
1	2
2	2
2	3

[ws_hgo]

if object_id('[TB]') is not null drop table [TB]    
 go    
 create table [TB](a varchar(3),b varchar(18))     
  insert [TB]     
  select '1',',2,' union all     
  select '2',',2,3,'     
  GO   

create view v_list
as
select B.a,substring(B.b,p.number,charindex(',',B.b+',',p.number)-p.number) b    
 from 
(
select a,substring(left(b,len(b)-1),2,len(b)-1) b from [TB]
) B    
 join master..spt_values p    
 on p.type='P'    
 and charindex(',',','+B.b,number)=number 

select * from v_list

a    b
---- ------------------
1    2
2    2
2    3

(3 行受影响)

[dawugui]

/*
标题：简单数据拆分(version 2.0)
作者：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间：2010-05-07
地点：重庆航天职业学院
描述：

有表tb, 如下:
id          value
----------- -----------
1           aa,bb
2           aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id          value
----------- --------
1           aa
1           bb
2           aaa
2           bbb
2           ccc
*/

--1. 旧的解决方法(sql server 2000)

create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go

--方法1.使用临时表完成
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b 

SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[value], B.id, 1) = ','

DROP TABLE #

--方法2.如果数据量小，可不使用临时表
select a.id , value = substring(a.value , b.number , charindex(',' , a.value + ',' , b.number) - b.number) 
from tb a join master..spt_values  b 
on b.type='p' and b.number between 1 and len(a.value)
where substring(',' + a.value , b.number , 1) = ','

--2. 新的解决方法(sql server 2005)
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go

--方法1.使用xml完成
SELECT A.id, B.value FROM
(
  SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
) A OUTER APPLY
(
  SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
) B

--方法2.使用CTE完成
;with tt as 
(select id,[value]=cast(left([value],charindex(',',[value]+',')-1) as nvarchar(100)),Split=cast(stuff([value]+',',1,charindex(',',[value]+','),'') as nvarchar(100)) from tb
union all
select id,[value]=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from tt where split>''
)
select id,[value] from tt order by id option (MAXRECURSION 0)


DROP TABLE tb

/*
id          value
----------- ------------------------------
1           aa
1           bb
2           aaa
2           bbb
2           ccc

(5 行受影响)
*/

[华夏小卒]

if object_id('[TB]') is not null drop table [TB]    
 go    
 create table [TB](a varchar(3),b varchar(18))     
  insert [TB]     
  select '1',',2,' union all     
  select '2',',2,3,'     
  GO     
 
select a,
b=substring(right(b,len(b)-1),number,charindex(',',right(b,len(b)-1),number)-number)
from tb t,master..spt_values s
where type='p' and number>0
and substring(left(b,len(b)-1),number,1)=','



a    b                  
---- ------------------ 
1    2
2    2
2    3

（所影响的行数为 3 行）