急求一个SQL视图

2011-01-05 10:50:09 153 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

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我有一张表A
a b
1 ,2,
2 ,2,3,

我想做个视图

a b
1 2
2 2
2 3

可以实现吗？

...全文

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华夏小卒 2011-01-05

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if object_id('[TB]') is not null drop table [TB]    

 go    

 create table [TB](a varchar(3),b varchar(18))     

  insert [TB]     

  select '1',',2,' union all     

  select '2',',2,3,'     

  GO     

 

select a,

b=substring(right(b,len(b)-1),number,charindex(',',right(b,len(b)-1),number)-number)

from tb t,master..spt_values s

where type='p' and number>0

and substring(left(b,len(b)-1),number,1)=','







a    b                  

---- ------------------ 

1    2

2    2

2    3



（所影响的行数为 3 行）

dawugui 2011-01-05

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/*

标题：简单数据拆分(version 2.0)

作者：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)

时间：2010-05-07

地点：重庆航天职业学院

描述：



有表tb, 如下:

id          value

----------- -----------

1           aa,bb

2           aaa,bbb,ccc

欲按id,分拆value列, 分拆后结果如下:

id          value

----------- --------

1           aa

1           bb

2           aaa

2           bbb

2           ccc

*/



--1. 旧的解决方法(sql server 2000)



create table tb(id int,value varchar(30))

insert into tb values(1,'aa,bb')

insert into tb values(2,'aaa,bbb,ccc')

go



--方法1.使用临时表完成

SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b 



SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id)

FROM tb A, # B

WHERE SUBSTRING(',' + A.[value], B.id, 1) = ','



DROP TABLE #



--方法2.如果数据量小，可不使用临时表

select a.id , value = substring(a.value , b.number , charindex(',' , a.value + ',' , b.number) - b.number) 

from tb a join master..spt_values  b 

on b.type='p' and b.number between 1 and len(a.value)

where substring(',' + a.value , b.number , 1) = ','



--2. 新的解决方法(sql server 2005)

create table tb(id int,value varchar(30))

insert into tb values(1,'aa,bb')

insert into tb values(2,'aaa,bbb,ccc')

go



--方法1.使用xml完成

SELECT A.id, B.value FROM

(

  SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb

) A OUTER APPLY

(

  SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)

) B



--方法2.使用CTE完成

;with tt as 

(select id,[value]=cast(left([value],charindex(',',[value]+',')-1) as nvarchar(100)),Split=cast(stuff([value]+',',1,charindex(',',[value]+','),'') as nvarchar(100)) from tb

union all

select id,[value]=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from tt where split>''

)

select id,[value] from tt order by id option (MAXRECURSION 0)





DROP TABLE tb



/*

id          value

----------- ------------------------------

1           aa

1           bb

2           aaa

2           bbb

2           ccc



(5 行受影响)

*/

ws_hgo 2011-01-05

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if object_id('[TB]') is not null drop table [TB]    

 go    

 create table [TB](a varchar(3),b varchar(18))     

  insert [TB]     

  select '1',',2,' union all     

  select '2',',2,3,'     

  GO   



create view v_list

as

select B.a,substring(B.b,p.number,charindex(',',B.b+',',p.number)-p.number) b    

 from 

(

select a,substring(left(b,len(b)-1),2,len(b)-1) b from [TB]

) B    

 join master..spt_values p    

 on p.type='P'    

 and charindex(',',','+B.b,number)=number 



select * from v_list



a    b

---- ------------------

1    2

2    2

2    3



(3 行受影响)

飘零一叶 2011-01-05

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CREATE TABLE A

(

  A INT,

  B VARCHAR(10) 

)

INSERT INTO A

SELECT 1,',2,' UNION ALL

SELECT 2,',2,3,'



CREATE VIEW VIEW_A

AS

SELECT A.A, B.value FROM

(

  SELECT A, B = CONVERT(xml,'<root><v>' + REPLACE(B, ',', '</v><v>') + '</v></root>') FROM A

) A OUTER APPLY

(

  SELECT value = N.v.value('.', 'varchar(100)') FROM A.B.nodes('/root/v') N(v)

) B

WHERE B.value<>''



SELECT * FROM VIEW_A

---------

A	value

1	2

2	2

2	3

华夏小卒 2011-01-05

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create view vv

as



select a,

b=substring(right(b,len(b)-1),charindex(right(b,len(b)-1),',',number)-number)

from a t,master..spt_values s

where type='p' and number>0

and substring(left(b,len(b)-1),len(b)-1),,number,1)=','

try

ws_hgo 2011-01-05

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if object_id('[TB]') is not null drop table [TB]    

 go    

 create table [TB]([COL1] varchar(3),[COL2] varchar(18))     

  insert [TB]     

  select 'ABC','123,4568,1234565' union all     

  select 'DBD','1231,56455,5645665'     

  GO     

     

 select B.[COL1],substring(B.[COL2],p.number,charindex(',',B.[COL2]+',',p.number)-p.number) [COL2]    

 from TB B    

 join master..spt_values p    

 on p.type='P'    

 and charindex(',',','+B.[COL2],number)=number     

     

COL1 COL2   

---- ------------------   

ABC  123   

ABC  4568   

ABC  1234565   

DBD  1231   

DBD  56455   

DBD  5645665   

(6 行受影响)  



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急求一个SQL视图

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