该字符串如何通过正则数组化呢

木头是猫 2011-01-11 11:31:43

字符串
167.000000:15:20000L：43243；sfdsf@$!@#)(*(_@:1627207:3232483;20509:28314;167.000000:15::1627207:3232483;20509:28315;167.000000:15::1627207:3232483;20509:28316;167.000000:15::1627207:3232484;20509:28314;167.000000:15::1627207:3232484;20509:28315;167.000000:15::1627207:3232484;20509:28316;

想通过正则数组化后变成
167.000000:15:20000L：43243；sfdsf@$!@#)(*(_@:1627207:3232483;20509:28314;
167.000000:15::1627207:3232483;20509:28315;
167.000000:15::1627207:3232483;20509:28316;
167.000000:15::1627207:3232484;20509:28314;
167.000000:15::1627207:3232484;20509:28315;
167.000000:15::1627207:3232484;20509:28316;

该如何操作呢？
规律大概就是
带6位小数的数字 + ":" + 数字 + ":" + 可为空的任意字符串 + ":" + 数字 + ":" + 数字 + ";" + 数字 + ":" + 数字 + ";"

...全文

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Mr-Jee 2011-01-11

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	var str = "167.000000:15:20000L：43243；sfdsf@$!@#)(*(_@:1627207:3232483;20509:28314;167.000000:15::1627207:3232483;20509:28315;167.000000:15::1627207:3232483;20509:28316;167.000000:15::1627207:3232484;20509:28314;167.000000:15::1627207:3232484;20509:28315;167.000000:15::1627207:3232484;20509:28316;";

	var reg = /\d+\.\d{6}:\d+:[^:]*:(\d+:\d+;){2}/g;

	var arr = [];

	var val;

	while(val = reg.exec(str)) {

		arr.push(val);

	}

	alert(arr.join("\r\n"));

Dogfish 2011-01-11

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'ar就是楼主要的。

s="167.000000:15:20000L：43243；sfdsf@$!@#)(*(_@:1627207:3232483;20509:28314;167.000000:15::1627207:3232483;20509:28315;167.000000:15::1627207:3232483;20509:28316;167.000000:15::1627207:3232484;20509:28314;167.000000:15::1627207:3232484;20509:28315;167.000000:15::1627207:3232484;20509:28316;"

Set myRegExp = New RegExp

myRegExp.IgnoreCase = True

myRegExp.Global = True

myRegExp.Pattern = "(\d)+.(\d){6}:(\d)+:([^:]*):((\d)+:(\d)+;){2}"

Set myMatches = myRegExp.Execute(s)

Dim ar()

ReDim ar(myMatches.count)

i=0

For Each myMatch in myMatches

	ar(i) = myMatch.Value

	i=i+1

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