如何依次显示字符串?

[清钟沁桐]

dsp0_annexFlat="dsp_c0_image image0"
dsp1_annexFlat="dsp_c1_image image1"
dsp2_annexFlat="dsp_c2_image image2"
dsp3_annexFlat="dsp_c3_image image3"
cpu1_annexFlat="cpu_c1_image image4"

group="dsp0 dsp1 dsp2 dsp3 cpu1"
for i in $group
do 
     echo $'${i}_annexFlat'
     echo ${dsp3_annexFlat}
     echo ${${i}_annexFlat}
done

以上代码执行时出错
${i}_annexFlat
dsp_c3_image image3
./hcc: line 20: ${${i}_annexFlat}: bad substitution
我想显示以下内容该怎么在for循环中操作呢？
"dsp_c1_image image1"
"dsp_c2_image image2"
"dsp_c3_image image"
"cpu_c1_image image4"

[iambic]

group="dsp0 dsp1 dsp2 dsp3 cpu1"
for i in $group
do 
     eval echo '$'${i}_annexFlat
done

[看着奢扣]

#!/bin/bash
dsp0_annexFlat="dsp_c0_image image0"
dsp1_annexFlat="dsp_c1_image image1"
dsp2_annexFlat="dsp_c2_image image2"
dsp3_annexFlat="dsp_c3_image image3"
cpu1_annexFlat="cpu_c1_image image4"

group="dsp0 dsp1 dsp2 dsp3 cpu1"
j="_annexFlat"
for i in $group
do
b=$i$j
eval echo \$$b
done

[清钟沁桐]

恩，eval 是关键！