［c++0x］如何将 lambda 对象压入容器中？

[fallening]

#include <iostream>
#include <vector>

using namespace std;

auto l1 = [](double d) { std::cout << d << std::endl; };
auto l2 = [](double d) { std::cout << d*d << std::endl; };

int main()
{
    vector<decltype(l1)> lambda_arr;
    lambda_arr.push_back( ( l1 ) );
    lambda_arr.push_back( ( l2 ) );

    for ( auto i = lambda_arr.begin(); i != lambda_arr.end(); ++i )
        i( 2.2 );

    return 0;
｝

[itslmde]

帮顶吧，C++里的lambda，可惜现在还没有正式发布。

[eastcowboy]

用std::tr1::function试试。
std::tr1::function<void()> l1 = [](double d) { std::cout << d << std::endl; };

[zhangsongcui]

[Quote=引用 2 楼 eastcowboy 的回复:]

用std::tr1::function试试。
std::tr1::function<void()> l1 = [](double d) { std::cout << d << std::endl; };
[/Quote]
#include <functional>
std::function<void(double)> l1= [](double d) { std::cout << d << std::endl; };

[zhangsongcui]

#include <iostream>
#include <vector>
#include <functional>

using namespace std;

void fn2(int b)
{
	cout << b*b << endl;
}

struct fn3
{
	void operator()(int c)
	{
		cout << c*c*c << endl;
	}
};

int main()
{
	std::function<void(int)> fn=[](int a){cout << a << endl;};
	vector<std::function<void(int)> > v;
	v.push_back(fn);
	v.push_back(fn2);
	v.push_back(fn3());
	v.push_back([](int d){cout << d*d*d*d << endl;});
	for (auto iter=v.begin(), end=v.end(); iter!=end; ++iter)
		(*iter)(2);
	system("PAUSE");
    return 0;
}

[healer_kx]

咕~~(╯﹏╰)b
估计得用boost的function。

[太乙]

道士好前卫～！

[muyu1990]

学习·····

[珍惜生命远离CPP]

vector<function<void(double)> > lambda_arr;

[fallening]

多谢楼上诸位，结贴了~~~~

许久没来，csdn 还是一如既往，藏龙卧虎哦~~