Json反序列化问题（求解C#）如题

[步恒者]

C#后台如何反序列化下面的JSON字符串。
使用Newtonsoft.Json.Net.dll　还是不行。相差远
现在想取出这里：
"ADDRESSEE": "[e-mail]",
"SEX": "2",
"PROVINCECODE": "32",
"CITYCODE": "394",
"AREACODE": "3350",
"POSTALCODE": "",
"ADDRESS": "[e-mail]",
"MOBILEPHONE": "1325555555",
"EMAIL": "[e-mail]",
"REGNAME": "[e-mail]"
和
"ADDCODE": "",
"TRANSFERID": "01",
"COUPANCODE": "",
"PAYMENTTYPEID": "20",
"NOSTOCKNOTIFY": "0",
"DELIVERY": "k002"

这里的数据。就是ROWS　对应的
JSON如下。

[
{
"DataType": "System.DataTable",
"TableName": "table1",
"Columns": [
{
"ColumnName": "ADDRESSEEID",
"DataType": "System.String"
},
{
"ColumnName": "ADDRESSEE",
"DataType": "System.String"
},
{
"ColumnName": "SEX",
"DataType": "System.String"
},
{
"ColumnName": "PROVINCECODE",
"DataType": "System.String"
},
{
"ColumnName": "CITYCODE",
"DataType": "System.String"
},
{
"ColumnName": "AREACODE",
"DataType": "System.String"
},
{
"ColumnName": "POSTALCODE",
"DataType": "System.String"
},
{
"ColumnName": "ADDRESS",
"DataType": "System.String"
},
{
"ColumnName": "MOBILEPHONE",
"DataType": "System.String"
},
{
"ColumnName": "EMAIL",
"DataType": "System.String"
},
{
"ColumnName": "REGNAME",
"DataType": "System.String"
}
],
"Rows": [
{
"ADDRESSEE": "[e-mail]",
"SEX": "2",
"PROVINCECODE": "32",
"CITYCODE": "394",
"AREACODE": "3350",
"POSTALCODE": "",
"ADDRESS": "[e-mail]",
"MOBILEPHONE": "1325555555",
"EMAIL": "[e-mail]",
"REGNAME": "[e-mail]"
}
]
},
{
"DataType": "System.DataTable",
"TableName": "table1",
"Columns": [
{
"ColumnName": "ADDCODE",
"DataType": "System.String"
},
{
"ColumnName": "TRANSFERID",
"DataType": "System.String"
},
{
"ColumnName": "COUPANCODE",
"DataType": "System.String"
},
{
"ColumnName": "PAYMENTTYPEID",
"DataType": "System.String"
},
{
"ColumnName": "NOSTOCKNOTIFY",
"DataType": "System.String"
},
{
"ColumnName": "DELIVERY",
"DataType": "System.String"
}
],
"Rows": [
{
"ADDCODE": "",
"TRANSFERID": "01",
"COUPANCODE": "",
"PAYMENTTYPEID": "20",
"NOSTOCKNOTIFY": "0",
"DELIVERY": "k002"
}
]
}
]

[步恒者]

在线等。。。

[shine_fly]

没搞懂意思，楼下的呢？

[IHandler]

先反序列化为集合对象，再取
参考这个里面的反序列化

[wuyq11]

http://topic.csdn.net/u/20100530/16/ca0830c1-c132-479d-83a0-0c9862330a00.html?16173

[步恒者]

[Quote=引用 4 楼 wuyq11 的回复:]
http://topic.csdn.net/u/20100530/16/ca0830c1-c132-479d-83a0-0c9862330a00.html?16173
[/Quote]

对不上。不行。
客户端是发送下面的数据到后台呀。

[
{
"DataType": "System.DataTable",
"TableName": "table1",
"Columns": [
{
"ColumnName": "ADDRESSEEID",
"DataType": "System.String"
},
{
"ColumnName": "ADDRESSEE",
"DataType": "System.String"
},
{
"ColumnName": "SEX",
"DataType": "System.String"
},
{
"ColumnName": "PROVINCECODE",
"DataType": "System.String"
},
{
"ColumnName": "CITYCODE",
"DataType": "System.String"
},
{
"ColumnName": "AREACODE",
"DataType": "System.String"
},
{
"ColumnName": "POSTALCODE",
"DataType": "System.String"
},
{
"ColumnName": "ADDRESS",
"DataType": "System.String"
},
{
"ColumnName": "MOBILEPHONE",
"DataType": "System.String"
},
{
"ColumnName": "EMAIL",
"DataType": "System.String"
},
{
"ColumnName": "REGNAME",
"DataType": "System.String"
}
],
"Rows": [
{
"ADDRESSEE": "[e-mail]",
"SEX": "2",
"PROVINCECODE": "32",
"CITYCODE": "394",
"AREACODE": "3350",
"POSTALCODE": "",
"ADDRESS": "[e-mail]",
"MOBILEPHONE": "1325555555",
"EMAIL": "[e-mail]",
"REGNAME": "[e-mail]"
}
]
},
{
"DataType": "System.DataTable",
"TableName": "table1",
"Columns": [
{
"ColumnName": "ADDCODE",
"DataType": "System.String"
},
{
"ColumnName": "TRANSFERID",
"DataType": "System.String"
},
{
"ColumnName": "COUPANCODE",
"DataType": "System.String"
},
{
"ColumnName": "PAYMENTTYPEID",
"DataType": "System.String"
},
{
"ColumnName": "NOSTOCKNOTIFY",
"DataType": "System.String"
},
{
"ColumnName": "DELIVERY",
"DataType": "System.String"
}
],
"Rows": [
{
"ADDCODE": "",
"TRANSFERID": "01",
"COUPANCODE": "",
"PAYMENTTYPEID": "20",
"NOSTOCKNOTIFY": "0",
"DELIVERY": "k002"
}
]
}
]

[步恒者]

没解决，不过，还要谢谢楼上几位

[以专业开发人员为伍]

[Quote=引用楼主 jacky_163 的回复:]
这里的数据。就是ROWS　对应的
[/Quote]

不是rows对应的。



[Quote=引用 6 楼 jacky_163 的回复:]
对不上。不行。
[/Quote]
首先要知道数据的对象原型，例如

class myClass
{
  public string DataType;
  public string TableName;
  MyColumn Columns[];
  MyRow Rows[];
}

然后才能反序列化一个myClass的对象上。

至于MyColumn、MyRow类型，你也一样需要自己去或者跟发送给你数据的人协同去“知道”（不可能凭空写程序），这是你们自己的事。这不属于技术问题而是模型定义问题，但是不做，也就无法使用技术。